y>x^2+3x-4

Lösung

y > x^{2} + 3 x - 4

(h, k) = (- \frac{3}{2}, - \frac{25}{4}), p = \frac{1}{4}

Schritte zur Lösung

y > x^{2} + 3 x - 4

Rewrite

y > x^{2} + 3 x - 4

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{25}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{25}{4}), p = \frac{1}{4}

y^{2} - 4 y - x + 3 = 0

(x + 3)^{2} = 24 (y + 3)

y - 2 x^{2} \geq 2

y - 3 x^{2} = 6

2 x^{2} - 8 y - 12 = 0