x^2-4x+12y-20=0

Lösung

x^{2} - 4 x + 12 y - 20 = 0

(h, k) = (2, 2), p = - 3

Schritte zur Lösung

x^{2} - 4 x + 12 y - 20 = 0

Rewrite

x^{2} - 4 x + 12 y - 20 = 0

in the standard form

4 (- 3) (y - 2) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = - 3

x^{2} - 2 x + y - 1 = 0

x = 36 - 6 y^{2}

x^{2} + 2 x + y - 3 = 0

2 x^{2} - y = 14

x^{2} - y + 9 = 2 x^{2} + 8 y - 2