2x^2+3x+y=-4

Lösung

2 x^{2} + 3 x + y = - 4

(h, k) = (- \frac{3}{4}, - \frac{23}{8}), p = - \frac{1}{8}

Schritte zur Lösung

2 x^{2} + 3 x + y = - 4

Rewrite

2 x^{2} + 3 x + y = - 4

in the standard form

4 (- \frac{1}{8}) (y - (- \frac{23}{8})) = (x - (- \frac{3}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{4}, - \frac{23}{8}), p = - \frac{1}{8}

x^{2} - 5 x + y = 0

(y + 1) (y + 1) = - 8 x

3 x^{2} + 30 x - 8 y + 75 = 0

- 2 x = y^{2} - 8 y + 30

y = 5 x^{2} - 20 x