x^2+34x+q(x)=0

Lösung

x^{2} + 34 x + q (x) = 0

(h, k) = (- 17, 289), p = - \frac{1}{4}

Schritte zur Lösung

x^{2} + 34 x + y = 0

Rewrite

x^{2} + 34 x + y = 0

in the standard form

4 (- \frac{1}{4}) (y - 289) = (x - (- 17))^{2}

Therefore parabola properties are:

(h, k) = (- 17, 289), p = - \frac{1}{4}

\frac{x}{I} n (2 x) = 4

y^{2} + 3 x - 8 y + 10 = 0

y - 48 \leq x^{2} - 14 x

x^{2} - 8 x + p (x) = 0

r + \frac{a}{n} = b^{2}