y^2=4x+9

Lösung

y^{2} = 4 x + 9

(h, k) = (- \frac{9}{4}, 0), p = 1

Schritte zur Lösung

y^{2} = 4 x + 9

Rewrite

y^{2} = 4 x + 9

in the standard form:

4 \cdot 1 \cdot (x - (- \frac{9}{4})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{4}, 0), p = 1

4 x + y^{2} = 32

2 x^{2} + y \geq 0

y^{2} - 5 x = 0

(x - 4.5)^{2} = - 4 (y - 5)

- 6 x^{2} - 3 y = 9