3000-p^2+2q=0

Lösung

3000 - p^{2} + 2 q = 0

(h, k) = (0, - 1500), p = \frac{1}{2}

Schritte zur Lösung

3000 - p^{2} + 2 q = 0

Rewrite

3000 - p^{2} + 2 q = 0

in the standard form:

4 \cdot \frac{1}{2} (q - (- 1500)) = (p - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 1500), p = \frac{1}{2}

x^{2} - 24 y = 0

(y + 6)^{2} = \frac{1}{2} (x - 2)

\frac{x ^{2}}{4} = 4 + z

x^{2} + 8 x - 8 y = 16

y = - x^{2} - 5 x - 2