3x^2+5y=7-2x

Lösung

3 x^{2} + 5 y = 7 - 2 x

(h, k) = (- \frac{1}{3}, \frac{22}{15}), p = - \frac{5}{12}

Schritte zur Lösung

3 x^{2} + 5 y = 7 - 2 x

Rewrite

3 x^{2} + 5 y = 7 - 2 x

in the standard form

4 (- \frac{5}{12}) (y - \frac{22}{15}) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, \frac{22}{15}), p = - \frac{5}{12}

y^{2} - 16 x - 17 = 0

(x - 2) 2 + y^{2} = 16

17 - x + v 169 - x^{2} > 0

y = - \frac{5}{y} x - 1

x^{2} - 6 y - 39 = 0