x=y^2-4y+17

Lösung

x = y^{2} - 4 y + 17

(h, k) = (13, 2), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} - 4 y + 17

Rewrite

x = y^{2} - 4 y + 17

in the standard form

4 \cdot \frac{1}{4} (x - 13) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (13, 2), p = \frac{1}{4}

r^{2} - 7 t + 6 = 0

x = 3 y^{2} - 1

2 (y + 5) = (x + 1)^{2}

5 x^{2} + 4 (y + 5) = 80

\frac{x ^{2}}{36} = 9 y