1f(x)=-5x^2+8

Lösung

1 f (x) = - 5 x^{2} + 8

(h, k) = (0, 8), p = - \frac{1}{20}

Schritte zur Lösung

1 \cdot y = - 5 x^{2} + 8

Rewrite

1 \cdot y = - 5 x^{2} + 8

in the standard form:

4 (- \frac{1}{20}) (y - 8) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 8), p = - \frac{1}{20}

(x + 3)^{2} = - y

9 x - 5 y^{2} = 2

x^{2} - 2 x = 8 y + 17

f (x) = - \frac{3}{2} (x + 8) (x + 4)

9 x^{2} + y = 10