(y+10)^2=x

Lösung

(y + 10)^{2} = x

(h, k) = (0, - 10), p = \frac{1}{4}

Schritte zur Lösung

(y + 10)^{2} = x

Rewrite

(y + 10)^{2} = x

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 10))^{2}

Therefore parabola properties are:

(h, k) = (0, - 10), p = \frac{1}{4}

(x + 1)^{2} = - 8 y + 16

4 x (x - 2) + 5 y - 4 = 0

1 x^{2} - 2 y - 15 = 0

x = 2 (y - 4)^{2} + 1

y = x^{2} + 11 x - 2