y^2=6x-10

Lösung

y^{2} = 6 x - 10

(h, k) = (\frac{5}{3}, 0), p = \frac{3}{2}

Schritte zur Lösung

y^{2} = 6 x - 10

Rewrite

y^{2} = 6 x - 10

in the standard form:

4 \cdot \frac{3}{2} (x - \frac{5}{3}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{3}, 0), p = \frac{3}{2}

x = 12 y - 2 y^{2}

x 3 + (y - 1)^{2} = 9

0 = x^{2} + 2 x + 7 - k (x)

8 x^{2} + 3 x + h (x) = 0

16 x + 2 y^{2} = 0