y>=-x^2-1

Lösung

y \geq - x^{2} - 1

(h, k) = (0, - 1), p = - \frac{1}{4}

Schritte zur Lösung

y \geq - x^{2} - 1

Rewrite

y \geq - x^{2} - 1

in the standard form:

4 (- \frac{1}{4}) (y - (- 1)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = - \frac{1}{4}

x = \frac{- 7 y + 4}{1 + 6 x}

y = - 1 (x - 2)^{2}

1 = \frac{y}{x ^{2} + 3}

x^{2} + y > 4 x - 4

(x - 3)^{2} = 16 (y + 1)