3r^2=12t-15

Lösung

3 r^{2} = 12 t - 15

(h, k) = (0, \frac{5}{4}), p = 1

Schritte zur Lösung

3 r^{2} = 12 t - 15

Rewrite

3 r^{2} = 12 t - 15

in the standard form:

4 \cdot 1 \cdot (t - \frac{5}{4}) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{5}{4}), p = 1

y^{2} - 2 y + 1 - 12 x + 7 - 1 = 0

x = 4 (y - 3)^{2} + 1

y^{2} - 6 y + 9 = 4 x - 20

y^{2} + x - y = 0

- 4 z^{2} + 2 y - 7 = 0