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Beliebt Geometry >

x=at^2

Lösung

x = a t^{2}

Lösung

(h, k) = (0, 0), p = \frac{1}{4 a}

Schritte zur Lösung

x = a t^{2}

Rewrite

x = a t^{2}

in the standard form:

4 \cdot \frac{1}{4 a} (x - 0) = (t - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 a}

Beliebte Beispiele

6 = a b^{- 2}

- 4 x^{2} + 8 y + 64 = 0

3(x+3/4)+3(y-1/2)^2=36

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

x=-5((y+9)/4)^2

x = - 5 (\frac{y + 9}{4})^{2}

x^2-10x-79y=-25-79

x^{2} - 10 x - 79 y = - 25 - 79