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Beliebt Geometry >

y^2-14y-4x+33=0

Lösung

y^{2} - 14 y - 4 x + 33 = 0

Lösung

(h, k) = (- 4, 7), p = 1

Schritte zur Lösung

y^{2} - 14 y - 4 x + 33 = 0

Rewrite

y^{2} - 14 y - 4 x + 33 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 4)) = (y - 7)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 7), p = 1

Graph

Beliebte Beispiele

(x-0)^2=4(-5/12)(y-0)

(x - 0)^{2} = 4 (- \frac{5}{12}) (y - 0)

s-25= 45/2 t-3/4 t^2-33-75

s - 25 = \frac{45}{2} t - \frac{3}{4} t^{2} - 33 - 75

2 x^{2} - 7 y \geq 21

y - 5 = (x + 1)^{2}

y^{2} - 6 x + 5 y - 11 = 0