y<x^2-x+4

Lösung

y < x^{2} - x + 4

(h, k) = (\frac{1}{2}, \frac{15}{4}), p = \frac{1}{4}

Schritte zur Lösung

y < x^{2} - x + 4

Rewrite

y < x^{2} - x + 4

in the standard form

4 \cdot \frac{1}{4} (y - \frac{15}{4}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{15}{4}), p = \frac{1}{4}

5 x^{2} - 3 y = 4

x = y^{2} + 4 y - 5

x = y^{2} + 4 y - 7

6 xx + 7 y = 7

x - \frac{1}{2} y^{2} = 0