x^2-6x+1-k(x)=0

Lösung

x^{2} - 6 x + 1 - k (x) = 0

(h, k) = (3, - 8), p = \frac{1}{4}

Schritte zur Lösung

x^{2} - 6 x + 1 - y = 0

Rewrite

x^{2} - 6 x + 1 - y = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 8)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 8), p = \frac{1}{4}

2 (2 x - S (x)) = - 4 x (x - 1)

9 y^{2} - 36 x = 0

4 - x^{2} \leq f (x)

F (x) = - 2 x^{2} + 6 x + 13

y 7 y = 3 x