y^2+12x+12y+96=0

Lösung

y^{2} + 12 x + 12 y + 96 = 0

(h, k) = (- 5, - 6), p = - 3

Schritte zur Lösung

y^{2} + 12 x + 12 y + 96 = 0

Rewrite

y^{2} + 12 x + 12 y + 96 = 0

in the standard form

4 (- 3) (x - (- 5)) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 6), p = - 3

2 x^{2} - 9 x + 7 = (x - \frac{9}{4})^{2} + y

- x^{2} + 2 x - 4 y = 6

y + 4 = x^{2}

x + y = y^{2} - 3

9 x^{2} - 16 y = 144