2x^2-y+7=0

Lösung

2 x^{2} - y + 7 = 0

(h, k) = (0, 7), p = \frac{1}{8}

Schritte zur Lösung

2 x^{2} - y + 7 = 0

Rewrite

2 x^{2} - y + 7 = 0

in the standard form:

4 \cdot \frac{1}{8} (y - 7) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 7), p = \frac{1}{8}

20 x - 4 y = - 4 x^{2}

2 x^{2} - 7 y = 0

(x + 5)^{2} = 24 (y - 4)

2 x^{2} - 7 y = 9

3 y = 6 x + 5 y^{2}