y^2+2y+4x-6=0

Lösung

y^{2} + 2 y + 4 x - 6 = 0

(h, k) = (\frac{7}{4}, - 1), p = - 1

Schritte zur Lösung

y^{2} + 2 y + 4 x - 6 = 0

Rewrite

y^{2} + 2 y + 4 x - 6 = 0

in the standard form

4 (- 1) (x - \frac{7}{4}) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{4}, - 1), p = - 1

(y - 2)^{2} = 2 (x - 3)

8 k (x) = 3 x^{2} + 4

x - 7 y^{2} = 0

f (x) (x)^{- 1} = 5 (x - 2)

2 x^{2} + 4 y - 6 = 0