px^2=-20y

Lösung

p x^{2} = - 20 y

(h, k) = (0, 0), p = - \frac{5}{p}

Schritte zur Lösung

p x^{2} = - 20 y

Rewrite

p x^{2} = - 20 y

in the standard form:

4 (- \frac{5}{p}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{5}{p}

(y + 5)^{(2)} = - 2 (x - 7)

(x - 3)^{2} = 8 (y + 5)

- y^{2} + x = 1

x^{2} + 6 x + 16 y + 25 = 0

2 x = y^{2} - 2 y + \frac{1}{3}