(x-3)/(2^2)-(y^2)/(2^2)=1

解

\frac{x - 3}{2 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

(h, k) = (7, 0), p = \frac{1}{4}

解答ステップ

\frac{x - 3}{2 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

\frac{x - 3}{2 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

を標準的な形式で書き換える:

4 \cdot \frac{1}{4} (x - 7) = (y - 0)^{2}

ゆえに放物線の特性は:

(h, k) = (7, 0), p = \frac{1}{4}