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受欢迎的 Geometry >

solvefor x,r(x)^2-10x+25=0

解答

求解

x, r (x)^{2} - 10 x + 25 = 0

解答

x = \frac{5 ( - r + 1 + 1 )}{r}, x = \frac{5 ( - - r + 1 + 1 )}{r}; r \neq = 0

求解步骤

r x^{2} - 10 x + 25 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 r \cdot 25}{2 r}

化简

(- 10)^{2} - 4 r \cdot 25 : 10 1 - r

x_{1, 2} = \frac{- ( - 10 ) \pm 10 1 - r}{2 r}; r \neq = 0

将解分隔开

x_{1} = \frac{- ( - 10 ) + 10 1 - r}{2 r}, x_{2} = \frac{- ( - 10 ) - 10 1 - r}{2 r}

x = \frac{- ( - 10 ) + 10 1 - r}{2 r} : \frac{5 ( - r + 1 + 1 )}{r}

x = \frac{- ( - 10 ) - 10 1 - r}{2 r} : \frac{5 ( - - r + 1 + 1 )}{r}

二次方程组的解是:

x = \frac{5 ( - r + 1 + 1 )}{r}, x = \frac{5 ( - - r + 1 + 1 )}{r}; r \neq = 0

作图

流行的例子

2 x^{2} = 7 y - 4

2 x^{2} + 4 x + z = 0

x = 8 + 2 x - y^{2}

y = 3 x^{2} - 30 x + 68

5y+4=((x+3)^2+1)/2

5 y + 4 = \frac{( x + 3 ) ^{2} + 1}{2}