y^2-4y+3=x

Lösung

y^{2} - 4 y + 3 = x

(h, k) = (- 1, 2), p = \frac{1}{4}

Schritte zur Lösung

y^{2} - 4 y + 3 = x

Rewrite

y^{2} - 4 y + 3 = x

in the standard form

4 \cdot \frac{1}{4} (x - (- 1)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = \frac{1}{4}

(x + 4)^{2} = 4 (y - 2)

x = 4 (y - 1)^{2} + 5

y = - x^{2} + 8 x - 17

3 x^{2} + 2 x - 5 y + 7 = 0

y + 2 = x^{2} - x