de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y=2x^2+5x-7

Lösung

foki

y = 2 x^{2} + 5 x - 7

Lösung

(- \frac{5}{4}, - 10)

Schritte zur Lösung

Rewrite

y = 2 x^{2} + 5 x - 7

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{81}{8})) = (x - (- \frac{5}{4}))^{2}

(h, k) = (- \frac{5}{4}, - \frac{81}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{5}{4}, - \frac{81}{8})

along the y-axis

(- \frac{5}{4}, - \frac{81}{8} + p)

= (- \frac{5}{4}, - \frac{81}{8} + \frac{1}{8})

Fasse zusammen

(- \frac{5}{4}, - 10)

Graph

Beliebte Beispiele

foki x^2+2y-6=0

foki (x-5)^2=12(y+3)