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Beliebt Geometry >

leitkurve y^2-y-x+1=0

Lösung

leitkurve

y^{2} - y - x + 1 = 0

Lösung

x = \frac{1}{2}

Schritte zur Lösung

Rewrite

y^{2} - y - x + 1 = 0

in the standard form

4 \cdot \frac{1}{4} (x - \frac{3}{4}) = (y - \frac{1}{2})^{2}

(h, k) = (\frac{3}{4}, \frac{1}{2}), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(\frac{3}{4}, \frac{1}{2})

x-coordinate

x = \frac{3}{4} - p

x = \frac{3}{4} - \frac{1}{4}

Fasse zusammen

x = \frac{1}{2}

Graph

Beliebte Beispiele

((x-5)^2)/4+((y+3)^2)/(16)=1

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

x^{2} = 6 y

foki ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1

f oc i \frac{( y - 3 ) ^{2}}{11} - \frac{( x + 1 ) ^{2}}{5} = 1

x^2+2x+y^2+4y=20

x^{2} + 2 x + y^{2} + 4 y = 20

x - y^{2} = 0