4<=-x^2-y

解答

4 \leq - x^{2} - y

(h, k) = (0, - 4), p = - \frac{1}{4}

求解步骤

4 \leq - x^{2} - y

将

4 \leq - x^{2} - y

改写为标准形式:

4 (- \frac{1}{4}) (y - (- 4)) = (x - 0)^{2}

因此抛物线性质是:

(h, k) = (0, - 4), p = - \frac{1}{4}

18 x^{2} - 64 x - 14 y + 150 = 0

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

ecce n t r i c i t y 36 x^{2} + y^{2} = 36

x^{2} - 4 x + y^{2} + 6 y - 12 = 0

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1