leitkurve-29x^2+1388x-10040

Lösung

leitkurve

- 29 x^{2} + 1388 x - 10040

y = \frac{761905}{116}

Schritte zur Lösung

Rewrite

y = - 29 x^{2} + 1388 x - 10040

in the standard form

4 (- \frac{1}{116}) (y - \frac{190476}{29}) = (x - \frac{694}{29})^{2}

(h, k) = (\frac{694}{29}, \frac{190476}{29}), p = - \frac{1}{116}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{694}{29}, \frac{190476}{29})

y-coordinate

y = \frac{190476}{29} - p

y = \frac{190476}{29} - (- \frac{1}{116})

Fasse zusammen

y = \frac{761905}{116}

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