軸 y=2250(0.015-0.001x)^2+6000x

解

軸

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

x = - \frac{5999.9325}{0.0045}

解答ステップ

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

を標準的な形式で書き換える

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

ゆえに放物線の特性は:

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

EN : P a r ab o l e S y mm e t ry A x i s T i tl e 2 Eq

x = - \frac{5999.9325}{0.0045}