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Beliebt Geometry >

4x^2+4y^2-16x+40y+67=0

Lösung

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

Lösung

(a, b) = (2, - 5), r = \frac{7}{2}

Schritte zur Lösung

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

Rewrite

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = \frac{7}{2}

Graph

Beliebte Beispiele

5 x^{2} + 5 y^{2} = 125

x^2+y^2-14x+2y=-14

x^{2} + y^{2} - 14 x + 2 y = - 14

4 x^{2} + 4 y^{2} - 16 = 0

4x^2+4y^2+12x+16y-11=0

4 x^{2} + 4 y^{2} + 12 x + 16 y - 11 = 0

x^{2} = 16 - y^{2}