18\div 6× (4-3)+6

解答

18 \div 6 \times (4 - 3) + 6

9

求解步骤

18 \div 6 \times (4 - 3) + 6

遵循 PEMDAS 运算顺序

计算括号内的值

(4 - 3) : 1

4 - 3

4 - 3 = 1

= 1

= 18 \div 6 \times 1 + 6

乘除（左右）

18 \div 6 \times 1 : 3

18 \div 6 \times 1

18 \div 6 = 3

= 3 \times 1

3 \times 1 = 3

= 3

= 3 + 6

加减（左右）

3 + 6 : 9

3 + 6

3 + 6 = 9

= 9

= 9

2^{3} \times 3^{2} \times 5

724 + 500 - (18 \times 42) - (72 \times 2)

6 [24 - 2 (6)]^{2}

4 + 5 (7 - 3) \div 2

\frac{- 3}{1} (\frac{- 11}{3} + \frac{1}{1})