簡約 (7+1)^2-((11+3^2))/4

解

簡約

(7 + 1)^{2} - \frac{( 11 + 3 ^{2} )}{4}

59

解答ステップ

(7 + 1)^{2} - \frac{11 + 3 ^{2}}{4}

(7 + 1)^{2} = 64

(7 + 1)^{2}

数を足す:

7 + 1 = 8

= 8^{2}

8^{2} = 64

= 64

\frac{11 + 3 ^{2}}{4} = 5

\frac{11 + 3 ^{2}}{4}

11 + 3^{2} = 20

11 + 3^{2}

3^{2} = 9

= 11 + 9

数を足す:

11 + 9 = 20

= 20

= \frac{20}{4}

数を割る:

\frac{20}{4} = 5

= 5

= 64 - 5

数を引く:

64 - 5 = 59

= 59