derivative f(x)=x^2+1

解答

导数

f (x) = x^{2} + 1

2 x

求解步骤

\frac{d}{d x} (x^{2} + 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

化简

= 2 x

s l o p e (2.3) (4.9)

mi d p o in t (15, - 3), (5, 12)

p er p e n d i c u l a r y = \frac{2}{3} x - 3, (0, - 3)

p o l a r (22, 22)

t an g e n t f (x) = ln (x), at x = 1