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شائع علم المثلثات >

cos(pi-arctan(1/3))

الحلّ

cos (π - arctan (\frac{1}{3}))

الحلّ

- \frac{3 10}{10}

+1

عشري

- 0.94868 \dots

خطوات الحلّ

cos (π - arctan (\frac{1}{3}))

Rewrite using trig identities:

cos (π) cos (arctan (\frac{1}{3})) + sin (π) sin (arctan (\frac{1}{3}))

cos (π - arctan (\frac{1}{3}))

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

:فعّل متطابقة الطرح لزوايا

= cos (π) cos (arctan (\frac{1}{3})) + sin (π) sin (arctan (\frac{1}{3}))

= cos (π) cos (arctan (\frac{1}{3})) + sin (π) sin (arctan (\frac{1}{3}))

استخدم المتطابقة الأساسيّة التالية:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

Rewrite using trig identities:

cos (arctan (\frac{1}{3})) = \frac{3 10}{10}

cos (arctan (\frac{1}{3}))

Rewrite using trig identities:

cos (arctan (\frac{1}{3})) = \frac{1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

cos (arctan (x)) = \frac{1 + x ^{2}}{1 + x ^{2}} :

استخدم المتطابقة التالية

= \frac{1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

= \frac{1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

بسّط

= \frac{3 10}{10}

استخدم المتطابقة الأساسيّة التالية:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Rewrite using trig identities:

sin (arctan (\frac{1}{3})) = \frac{10}{10}

sin (arctan (\frac{1}{3}))

Rewrite using trig identities:

sin (arctan (\frac{1}{3})) = \frac{( \frac{1}{3} ) 1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

sin (arctan (x)) = \frac{x 1 + x ^{2}}{1 + x ^{2}} :

استخدم المتطابقة التالية

= \frac{( \frac{1}{3} ) 1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

= \frac{\frac{1}{3} 1 + ( \frac{1}{3} ) ^{2}}{1 + ( \frac{1}{3} ) ^{2}}

بسّط

= \frac{10}{10}

= (- 1) \frac{3 10}{10} + 0 \cdot \frac{10}{10}

بسّط

= - \frac{3 10}{10}

أمثلة شائعة

arccos(3/(sqrt(29)))

arccos (\frac{3}{29})

\frac{18}{sin ( 3 2 ^{\circ} )}

\frac{sin ( \frac{π}{2} )}{π}

tan (- \frac{2 π}{7})

cos((sqrt(7))/4)

cos (\frac{7}{4})