cos(x)=(-sqrt(2))/2

Lösung

cos (x) = \frac{- 2}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Grad

x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (x) = \frac{- 2}{2}

Wende Bruchregel an:

\frac{- a}{b} = - \frac{a}{b}

cos (x) = - \frac{2}{2}

Allgemeine Lösung für

cos (x) = - \frac{2}{2}

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

sin^{2} (θ) + sin (θ) = 0

cos^{2} (θ) - sin^{2} (θ) = sin (θ) + 1

tan (x) = - \frac{1}{2}

sin (θ) + cos (θ) = 1

cos (x^{2}) = 0