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شائع علم المثلثات >

csc(3θ)=6sin(3θ),0<θ<2pi

الحلّ

csc (3 θ) = 6 sin (3 θ), 0 < θ < 2 π

الحلّ

θ = \frac{0.42053 \dots}{3}, θ = \frac{π - 0.42053 \dots}{3}, θ = \frac{0.42053 \dots + 2 π}{3}, θ = \frac{3 π - 0.42053 \dots}{3}, θ = \frac{0.42053 \dots + 4 π}{3}, θ = \frac{5 π - 0.42053 \dots}{3}, θ = \frac{π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 2 π}{3}, θ = \frac{3 π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 4 π}{3}, θ = \frac{5 π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 6 π}{3}

درجات

θ = 8.03161 \dots^{\circ}, θ = 51.96838 \dots^{\circ}, θ = 128.03161 \dots^{\circ}, θ = 171.96838 \dots^{\circ}, θ = 248.03161 \dots^{\circ}, θ = 291.96838 \dots^{\circ}, θ = 68.03161 \dots^{\circ}, θ = 111.96838 \dots^{\circ}, θ = 188.03161 \dots^{\circ}, θ = 231.96838 \dots^{\circ}, θ = 308.03161 \dots^{\circ}, θ = 351.96838 \dots^{\circ}

خطوات الحلّ

csc (3 θ) = 6 sin (3 θ), 0 < θ < 2 π

من الطرفين

6 sin (3 θ)

اطرح

csc (3 θ) - 6 sin (3 θ) = 0

Rewrite using trig identities

csc (3 θ) - 6 sin (3 θ)

sin (x) = \frac{1}{csc ( x )}

:Use the basic trigonometric identity

= csc (3 θ) - 6 \cdot \frac{1}{csc ( 3 θ )}

6 \cdot \frac{1}{csc ( 3 θ )} = \frac{6}{csc ( 3 θ )}

6 \cdot \frac{1}{csc ( 3 θ )}

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{1 \cdot 6}{csc ( 3 θ )}

1 \cdot 6 = 6 :

اضرب الأعداد

= \frac{6}{csc ( 3 θ )}

= csc (3 θ) - \frac{6}{csc ( 3 θ )}

csc (3 θ) - \frac{6}{csc ( 3 θ )} = 0

بالاستعانة بطريقة التعويض

csc (3 θ) - \frac{6}{csc ( 3 θ )} = 0

csc (3 θ) = u :

على افتراض أنّ

u - \frac{6}{u} = 0

u - \frac{6}{u} = 0 : u = 6, u = - 6

u - \frac{6}{u} = 0

u

اضرب الطرفين بـ

u - \frac{6}{u} = 0

u

اضرب الطرفين بـ

uu - \frac{6}{u} u = 0 \cdot u

بسّط

uu - \frac{6}{u} u = 0 \cdot u

uu

بسّط:

u^{2}

uu

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

uu = u^{1 + 1}

= u^{1 + 1}

1 + 1 = 2 :

اجمع الأعداد

= u^{2}

- \frac{6}{u} u

بسّط:

- 6

- \frac{6}{u} u

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= - \frac{6 u}{u}

u :

إلغ العوامل المشتركة

= - 6

0 \cdot u

بسّط:

0

0 \cdot u

0 \cdot a = 0

فعّل القانون

= 0

u^{2} - 6 = 0

u^{2} - 6 = 0

u^{2} - 6 = 0

u^{2} - 6 = 0

حلّ:

u = 6, u = - 6

u^{2} - 6 = 0

انقل

6

إلى الجانب الأيمن

u^{2} - 6 = 0

للطرفين

6

أضف

u^{2} - 6 + 6 = 0 + 6

بسّط

u^{2} = 6

u^{2} = 6

x = f (a), - f (a)

الحلول هي

x^{2} = f (a)

لـ

u = 6, u = - 6

u = 6, u = - 6

افحص الإجبات

جد نقاط غير معرّفة:

u = 0

وقم بمساواتها لصفر

u - \frac{6}{u}

خذ المقامات في

u = 0

النقاط التالية غير معرّفة

u = 0

ضمّ النقاط غير المعرّفة مع الحلول

u = 6, u = - 6

u = csc (3 θ)

استبدل مجددًا

csc (3 θ) = 6, csc (3 θ) = - 6

csc (3 θ) = 6, csc (3 θ) = - 6

csc (3 θ) = 6, 0 < θ < 2 π : θ = \frac{arccsc ( 6 )}{3}, θ = \frac{π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π - arccsc ( 6 )}{3}

csc (3 θ) = 6, 0 < θ < 2 π

Apply trig inverse properties

csc (3 θ) = 6

csc (3 θ) = 6 :

حلول عامّة لـ

csc (x) = a \Rightarrow x = arccsc (a) + 2 πn, x = π - arccsc (a) + 2 πn

3 θ = arccsc (6) + 2 πn, 3 θ = π - arccsc (6) + 2 πn

3 θ = arccsc (6) + 2 πn, 3 θ = π - arccsc (6) + 2 πn

3 θ = arccsc (6) + 2 πn

حلّ:

θ = \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = arccsc (6) + 2 πn

3

اقسم الطرفين على

3 θ = arccsc (6) + 2 πn

3

اقسم الطرفين على

\frac{3 θ}{3} = \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

بسّط

θ = \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = π - arccsc (6) + 2 πn

حلّ:

θ = \frac{π}{3} - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = π - arccsc (6) + 2 πn

3

اقسم الطرفين على

3 θ = π - arccsc (6) + 2 πn

3

اقسم الطرفين على

\frac{3 θ}{3} = \frac{π}{3} - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

بسّط

θ = \frac{π}{3} - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = \frac{π}{3} - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}, θ = \frac{π}{3} - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

0 < θ < 2 π :

حلول للمدى

θ = \frac{arccsc ( 6 )}{3}, θ = \frac{π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π - arccsc ( 6 )}{3}

csc (3 θ) = - 6, 0 < θ < 2 π : θ = \frac{π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 6 π}{3}

csc (3 θ) = - 6, 0 < θ < 2 π

Apply trig inverse properties

csc (3 θ) = - 6

csc (3 θ) = - 6 :

حلول عامّة لـ

csc (x) = - a \Rightarrow x = arccsc (- a) + 2 πn, x = π + arccsc (a) + 2 πn

3 θ = arccsc (- 6) + 2 πn, 3 θ = π + arccsc (6) + 2 πn

3 θ = arccsc (- 6) + 2 πn, 3 θ = π + arccsc (6) + 2 πn

3 θ = arccsc (- 6) + 2 πn

حلّ:

θ = - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = arccsc (- 6) + 2 πn

arccsc (- 6) + 2 πn

بسّط:

- arccsc (6) + 2 πn

arccsc (- 6) + 2 πn

arccsc (- x) = - arccsc (x) :

استخدم القانون التالي

arccsc (- 6) = - arccsc (6)

= - arccsc (6) + 2 πn

3 θ = - arccsc (6) + 2 πn

3

اقسم الطرفين على

3 θ = - arccsc (6) + 2 πn

3

اقسم الطرفين على

\frac{3 θ}{3} = - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

بسّط

θ = - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = π + arccsc (6) + 2 πn

حلّ:

θ = \frac{π}{3} + \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

3 θ = π + arccsc (6) + 2 πn

3

اقسم الطرفين على

3 θ = π + arccsc (6) + 2 πn

3

اقسم الطرفين على

\frac{3 θ}{3} = \frac{π}{3} + \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

بسّط

θ = \frac{π}{3} + \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = \frac{π}{3} + \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

θ = - \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}, θ = \frac{π}{3} + \frac{arccsc ( 6 )}{3} + \frac{2 πn}{3}

0 < θ < 2 π :

حلول للمدى

θ = \frac{π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 6 π}{3}

وحّد الحلول

θ = \frac{arccsc ( 6 )}{3}, θ = \frac{π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π - arccsc ( 6 )}{3}, θ = \frac{arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π - arccsc ( 6 )}{3}, θ = \frac{π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 2 π}{3}, θ = \frac{3 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 4 π}{3}, θ = \frac{5 π + arccsc ( 6 )}{3}, θ = \frac{- arccsc ( 6 ) + 6 π}{3}

أظهر الحلّ بالتمثيل العشريّ

θ = \frac{0.42053 \dots}{3}, θ = \frac{π - 0.42053 \dots}{3}, θ = \frac{0.42053 \dots + 2 π}{3}, θ = \frac{3 π - 0.42053 \dots}{3}, θ = \frac{0.42053 \dots + 4 π}{3}, θ = \frac{5 π - 0.42053 \dots}{3}, θ = \frac{π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 2 π}{3}, θ = \frac{3 π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 4 π}{3}, θ = \frac{5 π + 0.42053 \dots}{3}, θ = \frac{- 0.42053 \dots + 6 π}{3}

رسم

أمثلة شائعة

sqrt(3)tan(3θ)-1=0,0<= θ<= 2pi

3 tan (3 θ) - 1 = 0, 0 \leq θ \leq 2 π

(cot(θ)+1)(csc(θ)-1)=0

(cot (θ) + 1) (csc (θ) - 1) = 0

2sin(x)cos(x)=1

2 sin (x) cos (x) = 1

cos(x)sin(x)+2sin(x)=0

cos (x) sin (x) + 2 sin (x) = 0

cos(x)sin(x)=-sin(x)

cos (x) sin (x) = - sin (x)