ar

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

شائع علم المثلثات >

solvefor x,f[g]=cos(1/(x^2))

الحلّ

solve for

x, f [g] = cos (\frac{1}{x ^{2}})

الحلّ

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}, x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}

خطوات الحلّ

f [g] = cos (\frac{1}{x ^{2}})

بدّل الأطراف

cos (\frac{1}{x ^{2}}) = f [g]

(a) = a

:احذف الأقواس

cos (\frac{1}{x ^{2}}) = f g

Apply trig inverse properties

cos (\frac{1}{x ^{2}}) = f g

cos (\frac{1}{x ^{2}}) = f g :

حلول عامّة لـ

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

\frac{1}{x ^{2}} = arccos (f g) + 2 πn, \frac{1}{x ^{2}} = - arccos (f g) + 2 πn

\frac{1}{x ^{2}} = arccos (f g) + 2 πn, \frac{1}{x ^{2}} = - arccos (f g) + 2 πn

\frac{1}{x ^{2}} = arccos (f g) + 2 πn

حلّ:

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

\frac{1}{x ^{2}} = arccos (f g) + 2 πn

x^{2}

اضرب الطرفين بـ

\frac{1}{x ^{2}} = arccos (f g) + 2 πn

x^{2}

اضرب الطرفين بـ

\frac{1}{x ^{2}} x^{2} = arccos (f g) x^{2} + 2 πn x^{2}

بسّط

1 = arccos (f g) x^{2} + 2 πn x^{2}

1 = arccos (f g) x^{2} + 2 πn x^{2}

1 = arccos (f g) x^{2} + 2 πn x^{2}

حلّ:

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

1 = arccos (f g) x^{2} + 2 πn x^{2}

بدّل الأطراف

arccos (f g) x^{2} + 2 πn x^{2} = 1

arccos (f g) x^{2} + 2 πn x^{2}

حلل إلى عوامل:

x^{2} (arccos (f g) + 2 πn)

arccos (f g) x^{2} + 2 πn x^{2}

x^{2}

قم باخراج العامل المشترك

= x^{2} (arccos (f g) + 2 πn)

x^{2} (arccos (f g) + 2 πn) = 1

arccos (f g) + 2 πn; f \neq = \frac{cos ( - 2 πn )}{g}

اقسم الطرفين على

x^{2} (arccos (f g) + 2 πn) = 1

arccos (f g) + 2 πn; f \neq = \frac{cos ( - 2 πn )}{g}

اقسم الطرفين على

\frac{x ^{2} ( arccos ( f g ) + 2 πn )}{arccos ( f g ) + 2 πn} = \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

بسّط

x^{2} = \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

x^{2} = \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

x = f (a), - f (a)

الحلول هي

x^{2} = f (a)

لـ

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( - 2 πn )}{g}

\frac{1}{x ^{2}} = - arccos (f g) + 2 πn

حلّ:

x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

\frac{1}{x ^{2}} = - arccos (f g) + 2 πn

x^{2}

اضرب الطرفين بـ

\frac{1}{x ^{2}} = - arccos (f g) + 2 πn

x^{2}

اضرب الطرفين بـ

\frac{1}{x ^{2}} x^{2} = - arccos (f g) x^{2} + 2 πn x^{2}

بسّط

1 = - arccos (f g) x^{2} + 2 πn x^{2}

1 = - arccos (f g) x^{2} + 2 πn x^{2}

1 = - arccos (f g) x^{2} + 2 πn x^{2}

حلّ:

x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

1 = - arccos (f g) x^{2} + 2 πn x^{2}

بدّل الأطراف

- arccos (f g) x^{2} + 2 πn x^{2} = 1

- arccos (f g) x^{2} + 2 πn x^{2}

حلل إلى عوامل:

x^{2} (- arccos (f g) + 2 πn)

- arccos (f g) x^{2} + 2 πn x^{2}

x^{2}

قم باخراج العامل المشترك

= x^{2} (- arccos (f g) + 2 πn)

x^{2} (- arccos (f g) + 2 πn) = 1

- arccos (f g) + 2 πn; f \neq = \frac{cos ( 2 πn )}{g}

اقسم الطرفين على

x^{2} (- arccos (f g) + 2 πn) = 1

- arccos (f g) + 2 πn; f \neq = \frac{cos ( 2 πn )}{g}

اقسم الطرفين على

\frac{x ^{2} ( - arccos ( f g ) + 2 πn )}{- arccos ( f g ) + 2 πn} = \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

بسّط

x^{2} = \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

x^{2} = \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

x = f (a), - f (a)

الحلول هي

x^{2} = f (a)

لـ

x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}; f \neq = \frac{cos ( 2 πn )}{g}

x = \frac{1}{arccos ( f g ) + 2 πn}, x = - \frac{1}{arccos ( f g ) + 2 πn}, x = \frac{1}{- arccos ( f g ) + 2 πn}, x = - \frac{1}{- arccos ( f g ) + 2 πn}

رسم

أمثلة شائعة

2cos(pi/5 θ)=sqrt(3)

2 cos (\frac{π}{5} θ) = 3

2cos(x)-sin(2x)=0

2 cos (x) - sin (2 x) = 0

sin(x)tan(x)-6tan(x)=0

sin (x) tan (x) - 6 tan (x) = 0

tan(θ)=sin(θ)

tan (θ) = sin (θ)

2cos(x)-2sin(x)=0

2 cos (x) - 2 sin (x) = 0