sec(x)=sqrt(2),0<= x<= 2pi

Lösung

sec (x) = 2, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}

Grad

x = 4 5^{\circ}, x = 31 5^{\circ}

Schritte zur Lösung

sec (x) = 2, 0 \leq x \leq 2 π

Allgemeine Lösung für

sec (x) = 2

sec (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Lösungen für den Bereich

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}

cos (2 x) + cos (3 x) = 0

cos (θ) = - 0.73

csc (θ) = - 3

4 cos (x) - 2 = 2 tan (x) cot (x) - sec (x)

11 (1 - cos (θ)) = sin^{2} (θ)