ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

cot(x)(1-cos^2(x))= 1/2 sin^2(x)

解

cot (x) (1 - cos^{2} (x)) = \frac{1}{2} sin^{2} (x)

解

x = 1.10714 \dots + πn

+1

度

x = 63.43494 \dots^{\circ} + 18 0^{\circ} n

解答ステップ

cot (x) (1 - cos^{2} (x)) = \frac{1}{2} sin^{2} (x)

両辺から

\frac{1}{2} sin^{2} (x)

を引く

cot (x) (1 - cos^{2} (x)) - \frac{1}{2} sin^{2} (x) = 0

簡素化

cot (x) (1 - cos^{2} (x)) - \frac{1}{2} sin^{2} (x) : \frac{2 cot ( x ) ( 1 - cos ^{2} ( x ) ) - sin ^{2} ( x )}{2}

cot (x) (1 - cos^{2} (x)) - \frac{1}{2} sin^{2} (x)

\frac{1}{2} sin^{2} (x) = \frac{sin ^{2} ( x )}{2}

\frac{1}{2} sin^{2} (x)

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ^{2} ( x )}{2}

乗算:

1 \cdot sin^{2} (x) = sin^{2} (x)

= \frac{sin ^{2} ( x )}{2}

= cot (x) (- cos^{2} (x) + 1) - \frac{sin ^{2} ( x )}{2}

元を分数に変換する:

cot (x) (- cos^{2} (x) + 1) = \frac{cot ( x ) ( 1 - cos ^{2} ( x ) ) 2}{2}

= \frac{cot ( x ) ( 1 - cos ^{2} ( x ) ) \cdot 2}{2} - \frac{sin ^{2} ( x )}{2}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cot ( x ) ( 1 - cos ^{2} ( x ) ) \cdot 2 - sin ^{2} ( x )}{2}

\frac{2 cot ( x ) ( 1 - cos ^{2} ( x ) ) - sin ^{2} ( x )}{2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 cot (x) (1 - cos^{2} (x)) - sin^{2} (x) = 0

三角関数の公式を使用して書き換える

- sin^{2} (x) + (1 - cos^{2} (x)) \cdot 2 cot (x)

ピタゴラスの公式を使用する:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= - sin^{2} (x) + 2 cot (x) sin^{2} (x)

- sin^{2} (x) + 2 cot (x) sin^{2} (x) = 0

因数

- sin^{2} (x) + 2 cot (x) sin^{2} (x) : sin^{2} (x) (2 cot (x) - 1)

- sin^{2} (x) + 2 cot (x) sin^{2} (x)

共通項をくくり出す

sin^{2} (x)

= sin^{2} (x) (- 1 + 2 cot (x))

sin^{2} (x) (2 cot (x) - 1) = 0

各部分を別個に解く

sin^{2} (x) = 0 or 2 cot (x) - 1 = 0

sin^{2} (x) = 0 : x = 2 πn, x = π + 2 πn

sin^{2} (x) = 0

規則を適用

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

以下の一般解

sin (x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

2 cot (x) - 1 = 0 : x = arccot (\frac{1}{2}) + πn

2 cot (x) - 1 = 0

1

を右側に移動します

2 cot (x) - 1 = 0

両辺に

1

を足す

2 cot (x) - 1 + 1 = 0 + 1

簡素化

2 cot (x) = 1

2 cot (x) = 1

以下で両辺を割る

2

2 cot (x) = 1

以下で両辺を割る

2

\frac{2 cot ( x )}{2} = \frac{1}{2}

簡素化

cot (x) = \frac{1}{2}

cot (x) = \frac{1}{2}

三角関数の逆数プロパティを適用する

cot (x) = \frac{1}{2}

以下の一般解

cot (x) = \frac{1}{2}

cot (x) = a \Rightarrow x = arccot (a) + πn

x = arccot (\frac{1}{2}) + πn

x = arccot (\frac{1}{2}) + πn

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn, x = arccot (\frac{1}{2}) + πn

equationは以下で未定義のため:

2 πn, π + 2 πn

x = arccot (\frac{1}{2}) + πn

10進法形式で解を証明する

x = 1.10714 \dots + πn

グラフ

人気の例

(tan(x)-1)(2sin(x)-1)=0

(tan (x) - 1) (2 sin (x) - 1) = 0

cos (x) = \frac{20}{29}

2cot^4(x)-cot^2(x)-15=0

2 cot^{4} (x) - cot^{2} (x) - 15 = 0

cos(θ)=(sqrt(11))/6

cos (θ) = \frac{11}{6}

2 cot (θ) + 1 = 0