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受欢迎的三角函数 >

tan(-3x)=1

解答

tan (- 3 x) = 1

解答

x = - \frac{π}{12} - \frac{πn}{3}

+1

度数

x = - 1 5^{\circ} - 6 0^{\circ} n

求解步骤

tan (- 3 x) = 1

tan (- 3 x) = 1

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

- 3 x = \frac{π}{4} + πn

- 3 x = \frac{π}{4} + πn

解

- 3 x = \frac{π}{4} + πn : x = - \frac{π}{12} - \frac{πn}{3}

- 3 x = \frac{π}{4} + πn

两边除以

- 3

- 3 x = \frac{π}{4} + πn

两边除以

- 3

\frac{- 3 x}{- 3} = \frac{\frac{π}{4}}{- 3} + \frac{πn}{- 3}

化简

\frac{- 3 x}{- 3} = \frac{\frac{π}{4}}{- 3} + \frac{πn}{- 3}

化简

\frac{- 3 x}{- 3} : x

\frac{- 3 x}{- 3}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

\frac{\frac{π}{4}}{- 3} + \frac{πn}{- 3} : - \frac{π}{12} - \frac{πn}{3}

\frac{\frac{π}{4}}{- 3} + \frac{πn}{- 3}

\frac{\frac{π}{4}}{- 3} = - \frac{π}{12}

\frac{\frac{π}{4}}{- 3}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{π}{4}}{3}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{π}{4}}{3} = \frac{π}{4 \cdot 3}

= - \frac{π}{4 \cdot 3}

数字相乘:

4 \cdot 3 = 12

= - \frac{π}{12}

= - \frac{π}{12} + \frac{πn}{- 3}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{π}{12} - \frac{πn}{3}

x = - \frac{π}{12} - \frac{πn}{3}

x = - \frac{π}{12} - \frac{πn}{3}

x = - \frac{π}{12} - \frac{πn}{3}

x = - \frac{π}{12} - \frac{πn}{3}

作图

流行的例子

sin^2(x)=cos^2(x/2)

sin^{2} (x) = cos^{2} (\frac{x}{2})

(2 sin (x) - 1) = 0

solvefor x,sin(x)=y

so l v e f or x, sin (x) = y

cos(2x)=1-2sin(x)

cos (2 x) = 1 - 2 sin (x)

sin(θ-pi/3)-1=0

sin (θ - \frac{π}{3}) - 1 = 0