What is the general solution for cos(b)=0.3125 ?

The general solution for cos(b)=0.3125 is b=1.25297…+2pin,b=2pi-1.25297…+2pin

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cos(b)=0.3125

cos (b) = 0.3125

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

Degrees

b = 71.79004 \dots^{\circ} + 36 0^{\circ} n, b = 288.20995 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (b) = 0.3125

Apply trig inverse properties

cos (b) = 0.3125

General solutions for

cos (b) = 0.3125

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

b = arccos (0.3125) + 2 πn, b = 2 π - arccos (0.3125) + 2 πn

b = arccos (0.3125) + 2 πn, b = 2 π - arccos (0.3125) + 2 πn

Show solutions in decimal form

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

What is the general solution for cos(b)=0.3125 ?
The general solution for cos(b)=0.3125 is b=1.25297…+2pin,b=2pi-1.25297…+2pin