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Popular Trigonometry >

2sin(x)=csc(x)-6,0<= x<2pi

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Solution

2sin(x)=csc(x)−6,0≤x<2π

Solution

x=0.15898…,x=π−0.15898…
+1
Degrees
x=9.10895…∘,x=170.89104…∘
Solution steps
2sin(x)=csc(x)−6,0≤x<2π
Subtract csc(x)−6 from both sides2sin(x)−csc(x)+6=0
Rewrite using trig identities
6−csc(x)+2sin(x)
Use the basic trigonometric identity: sin(x)=csc(x)1​=6−csc(x)+2⋅csc(x)1​
2⋅csc(x)1​=csc(x)2​
2⋅csc(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=csc(x)1⋅2​
Multiply the numbers: 1⋅2=2=csc(x)2​
=6−csc(x)+csc(x)2​
6−csc(x)+csc(x)2​=0
Solve by substitution
6−csc(x)+csc(x)2​=0
Let: csc(x)=u6−u+u2​=0
6−u+u2​=0:u=3−11​,u=3+11​
6−u+u2​=0
Multiply both sides by u
6−u+u2​=0
Multiply both sides by u6u−uu+u2​u=0⋅u
Simplify
6u−uu+u2​u=0⋅u
Simplify −uu:−u2
−uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=−u1+1
Add the numbers: 1+1=2=−u2
Simplify u2​u:2
u2​u
Multiply fractions: a⋅cb​=ca⋅b​=u2u​
Cancel the common factor: u=2
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
6u−u2+2=0
6u−u2+2=0
6u−u2+2=0
Solve 6u−u2+2=0:u=3−11​,u=3+11​
6u−u2+2=0
Write in the standard form ax2+bx+c=0−u2+6u+2=0
Solve with the quadratic formula
−u2+6u+2=0
Quadratic Equation Formula:
For a=−1,b=6,c=2u1,2​=2(−1)−6±62−4(−1)⋅2​​
u1,2​=2(−1)−6±62−4(−1)⋅2​​
62−4(−1)⋅2​=211​
62−4(−1)⋅2​
Apply rule −(−a)=a=62+4⋅1⋅2​
Multiply the numbers: 4⋅1⋅2=8=62+8​
62=36=36+8​
Add the numbers: 36+8=44=44​
Prime factorization of 44:22⋅11
44
44divides by 244=22⋅2=2⋅22
22divides by 222=11⋅2=2⋅2⋅11
2,11 are all prime numbers, therefore no further factorization is possible=2⋅2⋅11
=22⋅11
=22⋅11​
Apply radical rule: =11​22​
Apply radical rule: 22​=2=211​
u1,2​=2(−1)−6±211​​
Separate the solutionsu1​=2(−1)−6+211​​,u2​=2(−1)−6−211​​
u=2(−1)−6+211​​:3−11​
2(−1)−6+211​​
Remove parentheses: (−a)=−a=−2⋅1−6+211​​
Multiply the numbers: 2⋅1=2=−2−6+211​​
Apply the fraction rule: −ba​=−ba​=−2−6+211​​
Cancel 2−6+211​​:11​−3
2−6+211​​
Factor −6+211​:2(−3+11​)
−6+211​
Rewrite as=−2⋅3+211​
Factor out common term 2=2(−3+11​)
=22(−3+11​)​
Divide the numbers: 22​=1=−3+11​
=−(11​−3)
Distribute parentheses=−(−3)−(11​)
Apply minus-plus rules−(−a)=a,−(a)=−a=3−11​
u=2(−1)−6−211​​:3+11​
2(−1)−6−211​​
Remove parentheses: (−a)=−a=−2⋅1−6−211​​
Multiply the numbers: 2⋅1=2=−2−6−211​​
Apply the fraction rule: −b−a​=ba​−6−211​=−(6+211​)=26+211​​
Factor 6+211​:2(3+11​)
6+211​
Rewrite as=2⋅3+211​
Factor out common term 2=2(3+11​)
=22(3+11​)​
Divide the numbers: 22​=1=3+11​
The solutions to the quadratic equation are:u=3−11​,u=3+11​
u=3−11​,u=3+11​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of 6−u+u2​ and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=3−11​,u=3+11​
Substitute back u=csc(x)csc(x)=3−11​,csc(x)=3+11​
csc(x)=3−11​,csc(x)=3+11​
csc(x)=3−11​,0≤x<2π:No Solution
csc(x)=3−11​,0≤x<2π
csc(x)≤−1orcsc(x)≥1NoSolution
csc(x)=3+11​,0≤x<2π:x=arccsc(3+11​),x=π−arccsc(3+11​)
csc(x)=3+11​,0≤x<2π
Apply trig inverse properties
csc(x)=3+11​
General solutions for csc(x)=3+11​csc(x)=a⇒x=arccsc(a)+2πn,x=π−arccsc(a)+2πnx=arccsc(3+11​)+2πn,x=π−arccsc(3+11​)+2πn
x=arccsc(3+11​)+2πn,x=π−arccsc(3+11​)+2πn
Solutions for the range 0≤x<2πx=arccsc(3+11​),x=π−arccsc(3+11​)
Combine all the solutionsx=arccsc(3+11​),x=π−arccsc(3+11​)
Show solutions in decimal formx=0.15898…,x=π−0.15898…

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Frequently Asked Questions (FAQ)

  • What is the general solution for 2sin(x)=csc(x)-6,0<= x<2pi ?

    The general solution for 2sin(x)=csc(x)-6,0<= x<2pi is x=0.15898…,x=pi-0.15898…
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