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受欢迎的三角函数 >

3tan^2(x/3)-1=0

解答

3 tan^{2} (\frac{x}{3}) - 1 = 0

解答

x = \frac{π}{2} + 3 πn, x = - \frac{π}{2} + 3 πn

+1

度数

x = 9 0^{\circ} + 54 0^{\circ} n, x = - 9 0^{\circ} + 54 0^{\circ} n

求解步骤

3 tan^{2} (\frac{x}{3}) - 1 = 0

用替代法求解

3 tan^{2} (\frac{x}{3}) - 1 = 0

令

: tan (\frac{x}{3}) = u

3 u^{2} - 1 = 0

3 u^{2} - 1 = 0 : u = \frac{1}{3}, u = - \frac{1}{3}

3 u^{2} - 1 = 0

将

1

到右边

3 u^{2} - 1 = 0

两边加上

1

3 u^{2} - 1 + 1 = 0 + 1

化简

3 u^{2} = 1

3 u^{2} = 1

两边除以

3

3 u^{2} = 1

两边除以

3

\frac{3 u ^{2}}{3} = \frac{1}{3}

化简

u^{2} = \frac{1}{3}

u^{2} = \frac{1}{3}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

u = \frac{1}{3}, u = - \frac{1}{3}

u = tan (\frac{x}{3})

代回

tan (\frac{x}{3}) = \frac{1}{3}, tan (\frac{x}{3}) = - \frac{1}{3}

tan (\frac{x}{3}) = \frac{1}{3}, tan (\frac{x}{3}) = - \frac{1}{3}

tan (\frac{x}{3}) = \frac{1}{3} : x = \frac{π}{2} + 3 πn

tan (\frac{x}{3}) = \frac{1}{3}

使用反三角函数性质

tan (\frac{x}{3}) = \frac{1}{3}

tan (\frac{x}{3}) = \frac{1}{3}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

\frac{x}{3} = arctan (\frac{1}{3}) + πn

\frac{x}{3} = arctan (\frac{1}{3}) + πn

解

\frac{x}{3} = arctan (\frac{1}{3}) + πn : x = \frac{π}{2} + 3 πn

\frac{x}{3} = arctan (\frac{1}{3}) + πn

化简

arctan (\frac{1}{3}) + πn : \frac{π}{6} + πn

arctan (\frac{1}{3}) + πn

使用以下普通恒等式:

arctan (\frac{1}{3}) = \frac{π}{6}

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{6} + πn

\frac{x}{3} = \frac{π}{6} + πn

在两边乘以

3

\frac{x}{3} = \frac{π}{6} + πn

在两边乘以

3

\frac{3 x}{3} = 3 \cdot \frac{π}{6} + 3 πn

化简

\frac{3 x}{3} = 3 \cdot \frac{π}{6} + 3 πn

化简

\frac{3 x}{3} : x

\frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

3 \cdot \frac{π}{6} + 3 πn : \frac{π}{2} + 3 πn

3 \cdot \frac{π}{6} + 3 πn

3 \cdot \frac{π}{6} = \frac{π}{2}

3 \cdot \frac{π}{6}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 3}{6}

约分:

3

= \frac{π}{2}

= \frac{π}{2} + 3 πn

x = \frac{π}{2} + 3 πn

x = \frac{π}{2} + 3 πn

x = \frac{π}{2} + 3 πn

x = \frac{π}{2} + 3 πn

tan (\frac{x}{3}) = - \frac{1}{3} : x = - \frac{π}{2} + 3 πn

tan (\frac{x}{3}) = - \frac{1}{3}

使用反三角函数性质

tan (\frac{x}{3}) = - \frac{1}{3}

tan (\frac{x}{3}) = - \frac{1}{3}

的通解

tan (x) = - a \Rightarrow x = arctan (- a) + πn

\frac{x}{3} = arctan (- \frac{1}{3}) + πn

\frac{x}{3} = arctan (- \frac{1}{3}) + πn

解

\frac{x}{3} = arctan (- \frac{1}{3}) + πn : x = - \frac{π}{2} + 3 πn

\frac{x}{3} = arctan (- \frac{1}{3}) + πn

化简

arctan (- \frac{1}{3}) + πn : - \frac{π}{6} + πn

arctan (- \frac{1}{3}) + πn

arctan (- \frac{1}{3}) = - \frac{π}{6}

arctan (- \frac{1}{3})

利用以下特性:

arctan (- x) = - arctan (x)

arctan (- \frac{1}{3}) = - arctan (\frac{1}{3})

= - arctan (\frac{1}{3})

使用以下普通恒等式:

arctan (\frac{1}{3}) = \frac{π}{6}

arctan (\frac{1}{3})

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

= - \frac{π}{6} + πn

\frac{x}{3} = - \frac{π}{6} + πn

在两边乘以

3

\frac{x}{3} = - \frac{π}{6} + πn

在两边乘以

3

\frac{3 x}{3} = - 3 \cdot \frac{π}{6} + 3 πn

化简

\frac{3 x}{3} = - 3 \cdot \frac{π}{6} + 3 πn

化简

\frac{3 x}{3} : x

\frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

- 3 \cdot \frac{π}{6} + 3 πn : - \frac{π}{2} + 3 πn

- 3 \cdot \frac{π}{6} + 3 πn

3 \cdot \frac{π}{6} = \frac{π}{2}

3 \cdot \frac{π}{6}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 3}{6}

约分:

3

= \frac{π}{2}

= - \frac{π}{2} + 3 πn

x = - \frac{π}{2} + 3 πn

x = - \frac{π}{2} + 3 πn

x = - \frac{π}{2} + 3 πn

x = - \frac{π}{2} + 3 πn

合并所有解

x = \frac{π}{2} + 3 πn, x = - \frac{π}{2} + 3 πn

作图

流行的例子

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