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Populaire Trigonométrie >

12cosh(2x)+7sinh(x)-24=0

Solution

12 cosh (2 x) + 7 sinh (x) - 24 = 0

Solution

x = ln (1.73025 \dots), x = ln (0.45623 \dots)

Degrés

x = 31.41360 \dots^{\circ}, x = - 44.96326 \dots^{\circ}

étapes des solutions

12 cosh (2 x) + 7 sinh (x) - 24 = 0

Récrire en utilisant des identités trigonométriques

12 cosh (2 x) + 7 sinh (x) - 24 = 0

Use the Hyperbolic identity:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

12 cosh (2 x) + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0

Use the Hyperbolic identity:

cosh (x) = \frac{e ^{x} + e ^{- x}}{2}

12 \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0

12 \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0

12 \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0 : x = ln (1.73025 \dots), x = ln (0.45623 \dots)

12 \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0

Appliquer les règles des exposants

12 \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 7 \cdot \frac{e ^{x} - e ^{- x}}{2} - 24 = 0

Appliquer la règle de l'exposant:

a^{b c} = (a^{b})^{c}

e^{2 x} = (e^{x})^{2}, e^{- 2 x} = (e^{x})^{- 2}, e^{- x} = (e^{x})^{- 1}

12 \cdot \frac{( e ^{x} ) ^{2} + ( e ^{x} ) ^{- 2}}{2} + 7 \cdot \frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2} - 24 = 0

12 \cdot \frac{( e ^{x} ) ^{2} + ( e ^{x} ) ^{- 2}}{2} + 7 \cdot \frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2} - 24 = 0

Récrire l'équation avec

e^{x} = u

12 \cdot \frac{( u ) ^{2} + ( u ) ^{- 2}}{2} + 7 \cdot \frac{u - ( u ) ^{- 1}}{2} - 24 = 0

Résoudre

12 \cdot \frac{u ^{2} + u ^{- 2}}{2} + 7 \cdot \frac{u - u ^{- 1}}{2} - 24 = 0 : u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

12 \cdot \frac{u ^{2} + u ^{- 2}}{2} + 7 \cdot \frac{u - u ^{- 1}}{2} - 24 = 0

Redéfinir

\frac{6 ( u ^{4} + 1 )}{u ^{2}} + \frac{7 ( u ^{2} - 1 )}{2 u} - 24 = 0

Multiplier par le PPCM

\frac{6 ( u ^{4} + 1 )}{u ^{2}} + \frac{7 ( u ^{2} - 1 )}{2 u} - 24 = 0

Trouver le plus petit commun multiple de

u^{2}, 2 u : 2 u^{2}

u^{2}, 2 u

Plus petit commun multiple (PPCM)

Calculer une expression composée de facteurs qui apparaissent soit dans

u^{2}

ou dans

2 u

= 2 u^{2}

Multipier par PPCM =

2 u^{2}

\frac{6 ( u ^{4} + 1 )}{u ^{2}} \cdot 2 u^{2} + \frac{7 ( u ^{2} - 1 )}{2 u} \cdot 2 u^{2} - 24 \cdot 2 u^{2} = 0 \cdot 2 u^{2}

Simplifier

\frac{6 ( u ^{4} + 1 )}{u ^{2}} \cdot 2 u^{2} + \frac{7 ( u ^{2} - 1 )}{2 u} \cdot 2 u^{2} - 24 \cdot 2 u^{2} = 0 \cdot 2 u^{2}

Simplifier

\frac{6 ( u ^{4} + 1 )}{u ^{2}} \cdot 2 u^{2} : 12 (u^{4} + 1)

\frac{6 ( u ^{4} + 1 )}{u ^{2}} \cdot 2 u^{2}

Multiplier des fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 ( u ^{4} + 1 ) \cdot 2 u ^{2}}{u ^{2}}

Annuler le facteur commun :

u^{2}

= 6 (u^{4} + 1) \cdot 2

Multiplier les nombres :

6 \cdot 2 = 12

= 12 (u^{4} + 1)

Simplifier

\frac{7 ( u ^{2} - 1 )}{2 u} \cdot 2 u^{2} : 7 u (u^{2} - 1)

\frac{7 ( u ^{2} - 1 )}{2 u} \cdot 2 u^{2}

Multiplier des fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 ( u ^{2} - 1 ) \cdot 2 u ^{2}}{2 u}

Annuler le facteur commun :

2

= \frac{7 ( u ^{2} - 1 ) u ^{2}}{u}

Annuler le facteur commun :

u

= 7 u (u^{2} - 1)

Simplifier

- 24 \cdot 2 u^{2} : - 48 u^{2}

- 24 \cdot 2 u^{2}

Multiplier les nombres :

24 \cdot 2 = 48

= - 48 u^{2}

Simplifier

0 \cdot 2 u^{2} : 0

0 \cdot 2 u^{2}

Appliquer la règle

0 \cdot a = 0

= 0

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} = 0

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} = 0

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} = 0

Résoudre

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} = 0 : u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} = 0

Développer

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2} : 12 u^{4} + 12 + 7 u^{3} - 7 u - 48 u^{2}

12 (u^{4} + 1) + 7 u (u^{2} - 1) - 48 u^{2}

Développer

12 (u^{4} + 1) : 12 u^{4} + 12

12 (u^{4} + 1)

Appliquer la loi de la distribution:

a (b + c) = ab + a c

a = 12, b = u^{4}, c = 1

= 12 u^{4} + 12 \cdot 1

Multiplier les nombres :

12 \cdot 1 = 12

= 12 u^{4} + 12

= 12 u^{4} + 12 + 7 u (u^{2} - 1) - 48 u^{2}

Développer

7 u (u^{2} - 1) : 7 u^{3} - 7 u

7 u (u^{2} - 1)

Appliquer la loi de la distribution:

a (b - c) = ab - a c

a = 7 u, b = u^{2}, c = 1

= 7 u u^{2} - 7 u \cdot 1

= 7 u^{2} u - 7 \cdot 1 \cdot u

Simplifier

7 u^{2} u - 7 \cdot 1 \cdot u : 7 u^{3} - 7 u

7 u^{2} u - 7 \cdot 1 \cdot u

7 u^{2} u = 7 u^{3}

7 u^{2} u

Appliquer la règle de l'exposant:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u = u^{2 + 1}

= 7 u^{2 + 1}

Additionner les nombres :

2 + 1 = 3

= 7 u^{3}

7 \cdot 1 \cdot u = 7 u

7 \cdot 1 \cdot u

Multiplier les nombres :

7 \cdot 1 = 7

= 7 u

= 7 u^{3} - 7 u

= 7 u^{3} - 7 u

= 12 u^{4} + 12 + 7 u^{3} - 7 u - 48 u^{2}

12 u^{4} + 12 + 7 u^{3} - 7 u - 48 u^{2} = 0

Ecrire sous la forme standard

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

12 u^{4} + 7 u^{3} - 48 u^{2} - 7 u + 12 = 0

Trouver une solution pour

12 u^{4} + 7 u^{3} - 48 u^{2} - 7 u + 12 = 0

par la méthode de Newton-Raphson:

u \approx 1.73025 \dots

12 u^{4} + 7 u^{3} - 48 u^{2} - 7 u + 12 = 0

Définition de l'approximation de Newton-Raphson

f (u) = 12 u^{4} + 7 u^{3} - 48 u^{2} - 7 u + 12

Trouver

f^{^{'}} (u) : 48 u^{3} + 21 u^{2} - 96 u - 7

\frac{d}{d u} (12 u^{4} + 7 u^{3} - 48 u^{2} - 7 u + 12)

Appliquer la règle de l'addition/soustraction:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (12 u^{4}) + \frac{d}{d u} (7 u^{3}) - \frac{d}{d u} (48 u^{2}) - \frac{d}{d u} (7 u) + \frac{d}{d u} (12)

\frac{d}{d u} (12 u^{4}) = 48 u^{3}

\frac{d}{d u} (12 u^{4})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 12 \frac{d}{d u} (u^{4})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 12 \cdot 4 u^{4 - 1}

Simplifier

= 48 u^{3}

\frac{d}{d u} (7 u^{3}) = 21 u^{2}

\frac{d}{d u} (7 u^{3})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d u} (u^{3})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 \cdot 3 u^{3 - 1}

Simplifier

= 21 u^{2}

\frac{d}{d u} (48 u^{2}) = 96 u

\frac{d}{d u} (48 u^{2})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 48 \frac{d}{d u} (u^{2})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 48 \cdot 2 u^{2 - 1}

Simplifier

= 96 u

\frac{d}{d u} (7 u) = 7

\frac{d}{d u} (7 u)

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d u}{d u}

Appliquer la dérivée commune:

\frac{d u}{d u} = 1

= 7 \cdot 1

Simplifier

= 7

\frac{d}{d u} (12) = 0

\frac{d}{d u} (12)

Dérivée d'une constante:

\frac{d}{d x} (a) = 0

= 0

= 48 u^{3} + 21 u^{2} - 96 u - 7 + 0

Simplifier

= 48 u^{3} + 21 u^{2} - 96 u - 7

Soit

u_{0} = 2

Calculer

u_{n + 1}

jusqu'à

Δ u_{n + 1} < 0.000001

u_{1} = 1.79925 \dots : Δ u_{1} = 0.20074 \dots

f (u_{0}) = 12 \cdot 2^{4} + 7 \cdot 2^{3} - 48 \cdot 2^{2} - 7 \cdot 2 + 12 = 54

f^{^{'}} (u_{0}) = 48 \cdot 2^{3} + 21 \cdot 2^{2} - 96 \cdot 2 - 7 = 269

u_{1} = 1.79925 \dots

Δ u_{1} = ∣ 1.79925 \dots - 2 ∣ = 0.20074 \dots

Δ u_{1} = 0.20074 \dots

u_{2} = 1.73639 \dots : Δ u_{2} = 0.06285 \dots

f (u_{1}) = 12 \cdot 1.79925 \dots^{4} + 7 \cdot 1.79925 \dots^{3} - 48 \cdot 1.79925 \dots^{2} - 7 \cdot 1.79925 \dots + 12 = 10.55028 \dots

f^{^{'}} (u_{1}) = 48 \cdot 1.79925 \dots^{3} + 21 \cdot 1.79925 \dots^{2} - 96 \cdot 1.79925 \dots - 7 = 167.84443 \dots

u_{2} = 1.73639 \dots

Δ u_{2} = ∣ 1.73639 \dots - 1.79925 \dots ∣ = 0.06285 \dots

Δ u_{2} = 0.06285 \dots

u_{3} = 1.73031 \dots : Δ u_{3} = 0.00608 \dots

f (u_{2}) = 12 \cdot 1.73639 \dots^{4} + 7 \cdot 1.73639 \dots^{3} - 48 \cdot 1.73639 \dots^{2} - 7 \cdot 1.73639 \dots + 12 = 0.85758 \dots

f^{^{'}} (u_{2}) = 48 \cdot 1.73639 \dots^{3} + 21 \cdot 1.73639 \dots^{2} - 96 \cdot 1.73639 \dots - 7 = 140.92085 \dots

u_{3} = 1.73031 \dots

Δ u_{3} = ∣ 1.73031 \dots - 1.73639 \dots ∣ = 0.00608 \dots

Δ u_{3} = 0.00608 \dots

u_{4} = 1.73025 \dots : Δ u_{4} = 0.00005 \dots

f (u_{3}) = 12 \cdot 1.73031 \dots^{4} + 7 \cdot 1.73031 \dots^{3} - 48 \cdot 1.73031 \dots^{2} - 7 \cdot 1.73031 \dots + 12 = 0.00759 \dots

f^{^{'}} (u_{3}) = 48 \cdot 1.73031 \dots^{3} + 21 \cdot 1.73031 \dots^{2} - 96 \cdot 1.73031 \dots - 7 = 138.42910 \dots

u_{4} = 1.73025 \dots

Δ u_{4} = ∣ 1.73025 \dots - 1.73031 \dots ∣ = 0.00005 \dots

Δ u_{4} = 0.00005 \dots

u_{5} = 1.73025 \dots : Δ u_{5} = 4.43112 E - 9

f (u_{4}) = 12 \cdot 1.73025 \dots^{4} + 7 \cdot 1.73025 \dots^{3} - 48 \cdot 1.73025 \dots^{2} - 7 \cdot 1.73025 \dots + 12 = 6.13297 E - 7

f^{^{'}} (u_{4}) = 48 \cdot 1.73025 \dots^{3} + 21 \cdot 1.73025 \dots^{2} - 96 \cdot 1.73025 \dots - 7 = 138.40674 \dots

u_{5} = 1.73025 \dots

Δ u_{5} = ∣ 1.73025 \dots - 1.73025 \dots ∣ = 4.43112 E - 9

Δ u_{5} = 4.43112 E - 9

u \approx 1.73025 \dots

Appliquer une division longue:

\frac{12 u ^{4} + 7 u ^{3} - 48 u ^{2} - 7 u + 12}{u - 1.73025 \dots} = 12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots

12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots \approx 0

Trouver une solution pour

12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots = 0

par la méthode de Newton-Raphson:

u \approx 0.45623 \dots

12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots = 0

Définition de l'approximation de Newton-Raphson

f (u) = 12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots

Trouver

f^{^{'}} (u) : 36 u^{2} + 55.52620 \dots u + 0.03734 \dots

\frac{d}{d u} (12 u^{3} + 27.76310 \dots u^{2} + 0.03734 \dots u - 6.93537 \dots)

Appliquer la règle de l'addition/soustraction:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (12 u^{3}) + \frac{d}{d u} (27.76310 \dots u^{2}) + \frac{d}{d u} (0.03734 \dots u) - \frac{d}{d u} (6.93537 \dots)

\frac{d}{d u} (12 u^{3}) = 36 u^{2}

\frac{d}{d u} (12 u^{3})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 12 \frac{d}{d u} (u^{3})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 12 \cdot 3 u^{3 - 1}

Simplifier

= 36 u^{2}

\frac{d}{d u} (27.76310 \dots u^{2}) = 55.52620 \dots u

\frac{d}{d u} (27.76310 \dots u^{2})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 27.76310 \dots \frac{d}{d u} (u^{2})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 27.76310 \dots \cdot 2 u^{2 - 1}

Simplifier

= 55.52620 \dots u

\frac{d}{d u} (0.03734 \dots u) = 0.03734 \dots

\frac{d}{d u} (0.03734 \dots u)

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.03734 \dots \frac{d u}{d u}

Appliquer la dérivée commune:

\frac{d u}{d u} = 1

= 0.03734 \dots \cdot 1

Simplifier

= 0.03734 \dots

\frac{d}{d u} (6.93537 \dots) = 0

\frac{d}{d u} (6.93537 \dots)

Dérivée d'une constante:

\frac{d}{d x} (a) = 0

= 0

= 36 u^{2} + 55.52620 \dots u + 0.03734 \dots - 0

Simplifier

= 36 u^{2} + 55.52620 \dots u + 0.03734 \dots

Soit

u_{0} = 1

Calculer

u_{n + 1}

jusqu'à

Δ u_{n + 1} < 0.000001

u_{1} = 0.6410682029 : Δ u_{1} = 0.3589317971

f (u_{0}) = 12 \cdot 1^{3} + 27.76310 \dots \cdot 1^{2} + 0.03734 \dots \cdot 1 - 6.93537 \dots = 32.86507 \dots

f^{^{'}} (u_{0}) = 36 \cdot 1^{2} + 55.52620 \dots \cdot 1 + 0.03734 \dots = 91.56355 \dots

u_{1} = 0.6410682029

Δ u_{1} = ∣ 0.6410682029 - 1 ∣ = 0.3589317971

Δ u_{1} = 0.3589317971

u_{2} = 0.48917 \dots : Δ u_{2} = 0.15189 \dots

f (u_{1}) = 12 \cdot 0.641068202 9^{3} + 27.76310 \dots \cdot 0.641068202 9^{2} + 0.03734 \dots \cdot 0.6410682029 - 6.93537 \dots = 7.65982 \dots

f^{^{'}} (u_{1}) = 36 \cdot 0.641068202 9^{2} + 55.52620 \dots \cdot 0.6410682029 + 0.03734 \dots = 50.42829 \dots

u_{2} = 0.48917 \dots

Δ u_{2} = ∣ 0.48917 \dots - 0.6410682029 ∣ = 0.15189 \dots

Δ u_{2} = 0.15189 \dots

u_{3} = 0.45759 \dots : Δ u_{3} = 0.03157 \dots

f (u_{2}) = 12 \cdot 0.48917 \dots^{3} + 27.76310 \dots \cdot 0.48917 \dots^{2} + 0.03734 \dots \cdot 0.48917 \dots - 6.93537 \dots = 1.13097 \dots

f^{^{'}} (u_{2}) = 36 \cdot 0.48917 \dots^{2} + 55.52620 \dots \cdot 0.48917 \dots + 0.03734 \dots = 35.81369 \dots

u_{3} = 0.45759 \dots

Δ u_{3} = ∣ 0.45759 \dots - 0.48917 \dots ∣ = 0.03157 \dots

Δ u_{3} = 0.03157 \dots

u_{4} = 0.45623 \dots : Δ u_{4} = 0.00136 \dots

f (u_{3}) = 12 \cdot 0.45759 \dots^{3} + 27.76310 \dots \cdot 0.45759 \dots^{2} + 0.03734 \dots \cdot 0.45759 \dots - 6.93537 \dots = 0.04487 \dots

f^{^{'}} (u_{3}) = 36 \cdot 0.45759 \dots^{2} + 55.52620 \dots \cdot 0.45759 \dots + 0.03734 \dots = 32.98387 \dots

u_{4} = 0.45623 \dots

Δ u_{4} = ∣ 0.45623 \dots - 0.45759 \dots ∣ = 0.00136 \dots

Δ u_{4} = 0.00136 \dots

u_{5} = 0.45623 \dots : Δ u_{5} = 2.49018 E - 6

f (u_{4}) = 12 \cdot 0.45623 \dots^{3} + 27.76310 \dots \cdot 0.45623 \dots^{2} + 0.03734 \dots \cdot 0.45623 \dots - 6.93537 \dots = 0.00008 \dots

f^{^{'}} (u_{4}) = 36 \cdot 0.45623 \dots^{2} + 55.52620 \dots \cdot 0.45623 \dots + 0.03734 \dots = 32.86358 \dots

u_{5} = 0.45623 \dots

Δ u_{5} = ∣ 0.45623 \dots - 0.45623 \dots ∣ = 2.49018 E - 6

Δ u_{5} = 2.49018 E - 6

u_{6} = 0.45623 \dots : Δ u_{6} = 8.33775 E - 12

f (u_{5}) = 12 \cdot 0.45623 \dots^{3} + 27.76310 \dots \cdot 0.45623 \dots^{2} + 0.03734 \dots \cdot 0.45623 \dots - 6.93537 \dots = 2.74007 E - 10

f^{^{'}} (u_{5}) = 36 \cdot 0.45623 \dots^{2} + 55.52620 \dots \cdot 0.45623 \dots + 0.03734 \dots = 32.86336 \dots

u_{6} = 0.45623 \dots

Δ u_{6} = ∣ 0.45623 \dots - 0.45623 \dots ∣ = 8.33775 E - 12

Δ u_{6} = 8.33775 E - 12

u \approx 0.45623 \dots

Appliquer une division longue:

\frac{12 u ^{3} + 27.76310 \dots u ^{2} + 0.03734 \dots u - 6.93537 \dots}{u - 0.45623 \dots} = 12 u^{2} + 33.23786 \dots u + 15.20147 \dots

12 u^{2} + 33.23786 \dots u + 15.20147 \dots \approx 0

Trouver une solution pour

12 u^{2} + 33.23786 \dots u + 15.20147 \dots = 0

par la méthode de Newton-Raphson:

u \approx - 0.57794 \dots

12 u^{2} + 33.23786 \dots u + 15.20147 \dots = 0

Définition de l'approximation de Newton-Raphson

f (u) = 12 u^{2} + 33.23786 \dots u + 15.20147 \dots

Trouver

f^{^{'}} (u) : 24 u + 33.23786 \dots

\frac{d}{d u} (12 u^{2} + 33.23786 \dots u + 15.20147 \dots)

Appliquer la règle de l'addition/soustraction:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (12 u^{2}) + \frac{d}{d u} (33.23786 \dots u) + \frac{d}{d u} (15.20147 \dots)

\frac{d}{d u} (12 u^{2}) = 24 u

\frac{d}{d u} (12 u^{2})

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 12 \frac{d}{d u} (u^{2})

Appliquer la règle de la puissance:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 12 \cdot 2 u^{2 - 1}

Simplifier

= 24 u

\frac{d}{d u} (33.23786 \dots u) = 33.23786 \dots

\frac{d}{d u} (33.23786 \dots u)

Retirer la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 33.23786 \dots \frac{d u}{d u}

Appliquer la dérivée commune:

\frac{d u}{d u} = 1

= 33.23786 \dots \cdot 1

Simplifier

= 33.23786 \dots

\frac{d}{d u} (15.20147 \dots) = 0

\frac{d}{d u} (15.20147 \dots)

Dérivée d'une constante:

\frac{d}{d x} (a) = 0

= 0

= 24 u + 33.23786 \dots + 0

Simplifier

= 24 u + 33.23786 \dots

Soit

u_{0} = 0

Calculer

u_{n + 1}

jusqu'à

Δ u_{n + 1} < 0.000001

u_{1} = - 0.45735 \dots : Δ u_{1} = 0.45735 \dots

f (u_{0}) = 12 \cdot 0^{2} + 33.23786 \dots \cdot 0 + 15.20147 \dots = 15.20147 \dots

f^{^{'}} (u_{0}) = 24 \cdot 0 + 33.23786 \dots = 33.23786 \dots

u_{1} = - 0.45735 \dots

Δ u_{1} = ∣ - 0.45735 \dots - 0 ∣ = 0.45735 \dots

Δ u_{1} = 0.45735 \dots

u_{2} = - 0.57010 \dots : Δ u_{2} = 0.11275 \dots

f (u_{1}) = 12 (- 0.45735 \dots)^{2} + 33.23786 \dots (- 0.45735 \dots) + 15.20147 \dots = 2.51007 \dots

f^{^{'}} (u_{1}) = 24 (- 0.45735 \dots) + 33.23786 \dots = 22.26136 \dots

u_{2} = - 0.57010 \dots

Δ u_{2} = ∣ - 0.57010 \dots - (- 0.45735 \dots) ∣ = 0.11275 \dots

Δ u_{2} = 0.11275 \dots

u_{3} = - 0.57791 \dots : Δ u_{3} = 0.00780 \dots

f (u_{2}) = 12 (- 0.57010 \dots)^{2} + 33.23786 \dots (- 0.57010 \dots) + 15.20147 \dots = 0.15256 \dots

f^{^{'}} (u_{2}) = 24 (- 0.57010 \dots) + 33.23786 \dots = 19.55525 \dots

u_{3} = - 0.57791 \dots

Δ u_{3} = ∣ - 0.57791 \dots - (- 0.57010 \dots) ∣ = 0.00780 \dots

Δ u_{3} = 0.00780 \dots

u_{4} = - 0.57794 \dots : Δ u_{4} = 0.00003 \dots

f (u_{3}) = 12 (- 0.57791 \dots)^{2} + 33.23786 \dots (- 0.57791 \dots) + 15.20147 \dots = 0.00073 \dots

f^{^{'}} (u_{3}) = 24 (- 0.57791 \dots) + 33.23786 \dots = 19.36801 \dots

u_{4} = - 0.57794 \dots

Δ u_{4} = ∣ - 0.57794 \dots - (- 0.57791 \dots) ∣ = 0.00003 \dots

Δ u_{4} = 0.00003 \dots

u_{5} = - 0.57794 \dots : Δ u_{5} = 8.81165 E - 10

f (u_{4}) = 12 (- 0.57794 \dots)^{2} + 33.23786 \dots (- 0.57794 \dots) + 15.20147 \dots = 1.70656 E - 8

f^{^{'}} (u_{4}) = 24 (- 0.57794 \dots) + 33.23786 \dots = 19.36711 \dots

u_{5} = - 0.57794 \dots

Δ u_{5} = ∣ - 0.57794 \dots - (- 0.57794 \dots) ∣ = 8.81165 E - 10

Δ u_{5} = 8.81165 E - 10

u \approx - 0.57794 \dots

Appliquer une division longue:

\frac{12 u ^{2} + 33.23786 \dots u + 15.20147 \dots}{u + 0.57794 \dots} = 12 u + 26.30249 \dots

12 u + 26.30249 \dots \approx 0

u \approx - 2.19187 \dots

Les solutions sont

u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

Vérifier les solutions

Trouver les points non définis (singularité):

u = 0

Prendre le(s) dénominateur(s) de

12 \frac{u ^{2} + u ^{- 2}}{2} + 7 \frac{u - u ^{- 1}}{2} - 24

et le comparer à zéro

Résoudre

u^{2} = 0 : u = 0

u^{2} = 0

Appliquer la règle

x^{n} = 0 \Rightarrow x = 0

u = 0

u = 0

Les points suivants ne sont pas définis

u = 0

Combiner des points indéfinis avec des solutions :

u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

u \approx 1.73025 \dots, u \approx 0.45623 \dots, u \approx - 0.57794 \dots, u \approx - 2.19187 \dots

Resubstituer

u = e^{x},

résoudre pour

x

Résoudre

e^{x} = 1.73025 \dots : x = ln (1.73025 \dots)

e^{x} = 1.73025 \dots

Appliquer les règles des exposants

e^{x} = 1.73025 \dots

f (x) = g (x)

, alors

ln (f (x)) = ln (g (x))

ln (e^{x}) = ln (1.73025 \dots)

Appliquer la loi des logarithmes:

ln (e^{a}) = a

ln (e^{x}) = x

x = ln (1.73025 \dots)

x = ln (1.73025 \dots)

Résoudre

e^{x} = 0.45623 \dots : x = ln (0.45623 \dots)

e^{x} = 0.45623 \dots

Appliquer les règles des exposants

e^{x} = 0.45623 \dots

f (x) = g (x)

, alors

ln (f (x)) = ln (g (x))

ln (e^{x}) = ln (0.45623 \dots)

Appliquer la loi des logarithmes:

ln (e^{a}) = a

ln (e^{x}) = x

x = ln (0.45623 \dots)

x = ln (0.45623 \dots)

Résoudre

e^{x} = - 0.57794 \dots :

Aucune solution pour

x \in R

e^{x} = - 0.57794 \dots

a^{f (x)}

ne peut pas être nulle ou négative pour

x \in R

Aucune solution pour x \in R

Résoudre

e^{x} = - 2.19187 \dots :

Aucune solution pour

x \in R

e^{x} = - 2.19187 \dots

a^{f (x)}

ne peut pas être nulle ou négative pour

x \in R

Aucune solution pour x \in R

x = ln (1.73025 \dots), x = ln (0.45623 \dots)

x = ln (1.73025 \dots), x = ln (0.45623 \dots)

Graphe

Exemples populaires

sec^2(θ)-1=0

2sin(θ)cos(θ)=-sin(θ)

sec(θ)= 7/6

2cos^2(x)+7sin(x)-5=0

8tan(2x)-16cos(x)=0