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受欢迎的三角函数 >

r=2acos(x)

解答

r = 2 a cos (x)

解答

x = arccos (\frac{r}{2 a}) + 2 πn, x = - arccos (\frac{r}{2 a}) + 2 πn

求解步骤

r = 2 a cos (x)

交换两边

2 a cos (x) = r

两边除以

2 a; a \neq = 0

2 a cos (x) = r

两边除以

2 a; a \neq = 0

\frac{2 a cos ( x )}{2 a} = \frac{r}{2 a}; a \neq = 0

化简

cos (x) = \frac{r}{2 a}; a \neq = 0

cos (x) = \frac{r}{2 a}; a \neq = 0

使用反三角函数性质

cos (x) = \frac{r}{2 a}

cos (x) = \frac{r}{2 a}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (\frac{r}{2 a}) + 2 πn, x = - arccos (\frac{r}{2 a}) + 2 πn

x = arccos (\frac{r}{2 a}) + 2 πn, x = - arccos (\frac{r}{2 a}) + 2 πn

作图

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