What is the general solution for tan(3B+5)=cot(2B+10) ?

The general solution for tan(3B+5)=cot(2B+10) is B=15+(360n)/5 ,B=51+(360n)/5

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Popular Trigonometry >

tan(3B+5)=cot(2B+10)

Solution

tan (3 B + 5^{\circ}) = cot (2 B + 1 0^{\circ})

Solution

B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}, B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

Radians

B = \frac{π}{12} + \frac{2 π}{5} n, B = \frac{17 π}{60} + \frac{2 π}{5} n

Solution steps

tan (3 B + 5^{\circ}) = cot (2 B + 1 0^{\circ})

Subtract

cot (2 B + 1 0^{\circ})

from both sides

tan (3 B + 5^{\circ}) - cot (2 B + 1 0^{\circ}) = 0

Simplify

tan (3 B + 5^{\circ}) - cot (2 B + 1 0^{\circ}) : tan (\frac{108 B + 18 0 ^{\circ}}{36}) - cot (\frac{36 B + 18 0 ^{\circ}}{18})

tan (3 B + 5^{\circ}) - cot (2 B + 1 0^{\circ})

Join

3 B + 5^{\circ} : \frac{108 B + 18 0 ^{\circ}}{36}

3 B + 5^{\circ}

Convert element to fraction:

3 B = \frac{3 B 36}{36}

= \frac{3 B \cdot 36}{36} + 5^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 B \cdot 36 + 18 0 ^{\circ}}{36}

Multiply the numbers:

3 \cdot 36 = 108

= \frac{108 B + 18 0 ^{\circ}}{36}

= tan (\frac{108 B + 18 0 ^{\circ}}{36}) - cot (2 B + 1 0^{\circ})

Join

2 B + 1 0^{\circ} : \frac{36 B + 18 0 ^{\circ}}{18}

2 B + 1 0^{\circ}

Convert element to fraction:

2 B = \frac{2 B 18}{18}

= \frac{2 B \cdot 18}{18} + 1 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 B \cdot 18 + 18 0 ^{\circ}}{18}

Multiply the numbers:

2 \cdot 18 = 36

= \frac{36 B + 18 0 ^{\circ}}{18}

= tan (\frac{108 B + 18 0 ^{\circ}}{36}) - cot (\frac{36 B + 18 0 ^{\circ}}{18})

tan (\frac{108 B + 18 0 ^{\circ}}{36}) - cot (\frac{36 B + 18 0 ^{\circ}}{18}) = 0

Express with sin, cos

- cot (\frac{18 0 ^{\circ} + 36 B}{18}) + tan (\frac{18 0 ^{\circ} + 108 B}{36})

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= - \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} + tan (\frac{18 0 ^{\circ} + 108 B}{36})

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} + \frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} )}

Simplify

- \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} + \frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} )} : \frac{- cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} ) + sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}{sin ( \frac{36 B + 18 0 ^{\circ}}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}

- \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} + \frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} )}

Least Common Multiplier of

sin (\frac{18 0 ^{\circ} + 36 B}{18}), cos (\frac{18 0 ^{\circ} + 108 B}{36}) : sin (\frac{36 B + 18 0 ^{\circ}}{18}) cos (\frac{108 B + 18 0 ^{\circ}}{36})

sin (\frac{18 0 ^{\circ} + 36 B}{18}), cos (\frac{18 0 ^{\circ} + 108 B}{36})

Lowest Common Multiplier (LCM)

Compute an expression comprised of factors that appear either in

sin (\frac{18 0 ^{\circ} + 36 B}{18})

cos (\frac{18 0 ^{\circ} + 108 B}{36})

= sin (\frac{36 B + 18 0 ^{\circ}}{18}) cos (\frac{108 B + 18 0 ^{\circ}}{36})

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

sin (\frac{36 B + 18 0 ^{\circ}}{18}) cos (\frac{108 B + 18 0 ^{\circ}}{36})

For

\frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} :

multiply the denominator and numerator by

cos (\frac{108 B + 18 0 ^{\circ}}{36})

\frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} = \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}

For

\frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} )} :

multiply the denominator and numerator by

sin (\frac{36 B + 18 0 ^{\circ}}{18})

\frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} )} = \frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}

= - \frac{cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}{sin ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )} + \frac{sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} ) + sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}{sin ( \frac{36 B + 18 0 ^{\circ}}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}

= \frac{- cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} ) + sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{36 B + 18 0 ^{\circ}}{18} )}{sin ( \frac{36 B + 18 0 ^{\circ}}{18} ) cos ( \frac{108 B + 18 0 ^{\circ}}{36} )}

\frac{- cos ( \frac{18 0 ^{\circ} + 108 B}{36} ) cos ( \frac{18 0 ^{\circ} + 36 B}{18} ) + sin ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{18 0 ^{\circ} + 36 B}{18} )}{cos ( \frac{18 0 ^{\circ} + 108 B}{36} ) sin ( \frac{18 0 ^{\circ} + 36 B}{18} )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- cos (\frac{18 0 ^{\circ} + 108 B}{36}) cos (\frac{18 0 ^{\circ} + 36 B}{18}) + sin (\frac{18 0 ^{\circ} + 108 B}{36}) sin (\frac{18 0 ^{\circ} + 36 B}{18}) = 0

Rewrite using trig identities

- cos (\frac{18 0 ^{\circ} + 108 B}{36}) cos (\frac{18 0 ^{\circ} + 36 B}{18}) + sin (\frac{18 0 ^{\circ} + 108 B}{36}) sin (\frac{18 0 ^{\circ} + 36 B}{18})

Use the Angle Sum identity:

cos (s) cos (t) - sin (s) sin (t) = cos (s + t)

- cos (s) cos (t) + sin (s) sin (t) = - cos (s + t)

= - cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18})

- cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18}) = 0

Divide both sides by

- 1

- cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18}) = 0

Divide both sides by

- 1

\frac{- cos ( \frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} )}{- 1} = \frac{0}{- 1}

Simplify

cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18}) = 0

cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18}) = 0

General solutions for

cos (\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18}) = 0

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 9 0^{\circ} + 36 0^{\circ} n, \frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 27 0^{\circ} + 36 0^{\circ} n

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 9 0^{\circ} + 36 0^{\circ} n, \frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 27 0^{\circ} + 36 0^{\circ} n

Solve

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 9 0^{\circ} + 36 0^{\circ} n : B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 9 0^{\circ} + 36 0^{\circ} n

Multiply by LCM

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 9 0^{\circ} + 36 0^{\circ} n

Find Least Common Multiplier of

36, 18, 2 : 36

36, 18, 2

Least Common Multiplier (LCM)

Prime factorization of

36 : 2 \cdot 2 \cdot 3 \cdot 3

36

36

divides by

236 = 18 \cdot 2

= 2 \cdot 18

18

divides by

218 = 9 \cdot 2

= 2 \cdot 2 \cdot 9

9

divides by

39 = 3 \cdot 3

= 2 \cdot 2 \cdot 3 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3 \cdot 3

Prime factorization of

18 : 2 \cdot 3 \cdot 3

18

18

divides by

218 = 9 \cdot 2

= 2 \cdot 9

9

divides by

39 = 3 \cdot 3

= 2 \cdot 3 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 3

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Compute a number comprised of factors that appear in at least one of the following:

36, 18, 2

= 2 \cdot 2 \cdot 3 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 \cdot 3 = 36

= 36

Multiply by LCM=

36

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 + \frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 = 9 0^{\circ} \cdot 36 + 36 0^{\circ} n \cdot 36

Simplify

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 + \frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 = 9 0^{\circ} \cdot 36 + 36 0^{\circ} n \cdot 36

Simplify

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 : 18 0^{\circ} + 108 B

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 18 0 ^{\circ} + 108 B ) \cdot 36}{36}

Cancel the common factor:

36

= 18 0^{\circ} + 108 B

Simplify

\frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 : 2 (36 B + 18 0^{\circ})

\frac{18 0 ^{\circ} + 36 B}{18} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 18 0 ^{\circ} + 36 B ) \cdot 36}{18}

Divide the numbers:

\frac{36}{18} = 2

= 2 (36 B + 18 0^{\circ})

Simplify

9 0^{\circ} \cdot 36 : 324 0^{\circ}

9 0^{\circ} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 324 0^{\circ}

Divide the numbers:

\frac{36}{2} = 18

= 324 0^{\circ}

Simplify

36 0^{\circ} n \cdot 36 : 1296 0^{\circ} n

36 0^{\circ} n \cdot 36

Multiply the numbers:

2 \cdot 36 = 72

= 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 324 0^{\circ} + 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 324 0^{\circ} + 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 324 0^{\circ} + 1296 0^{\circ} n

Expand

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) : 180 B + 54 0^{\circ}

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ})

Expand

2 (36 B + 18 0^{\circ}) : 72 B + 36 0^{\circ}

2 (36 B + 18 0^{\circ})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = 36 B, c = 18 0^{\circ}

= 2 \cdot 36 B + 36 0^{\circ}

Multiply the numbers:

2 \cdot 36 = 72

= 72 B + 36 0^{\circ}

= 18 0^{\circ} + 108 B + 72 B + 36 0^{\circ}

Simplify

18 0^{\circ} + 108 B + 72 B + 36 0^{\circ} : 180 B + 54 0^{\circ}

18 0^{\circ} + 108 B + 72 B + 36 0^{\circ}

Group like terms

= 108 B + 72 B + 18 0^{\circ} + 36 0^{\circ}

Add similar elements:

108 B + 72 B = 180 B

= 180 B + 18 0^{\circ} + 36 0^{\circ}

Add similar elements:

18 0^{\circ} + 36 0^{\circ} = 54 0^{\circ}

= 180 B + 54 0^{\circ}

= 180 B + 54 0^{\circ}

180 B + 54 0^{\circ} = 324 0^{\circ} + 1296 0^{\circ} n

Move

54 0^{\circ}

to the right side

180 B + 54 0^{\circ} = 324 0^{\circ} + 1296 0^{\circ} n

Subtract

54 0^{\circ}

from both sides

180 B + 54 0^{\circ} - 54 0^{\circ} = 324 0^{\circ} + 1296 0^{\circ} n - 54 0^{\circ}

Simplify

180 B = 270 0^{\circ} + 1296 0^{\circ} n

180 B = 270 0^{\circ} + 1296 0^{\circ} n

Divide both sides by

180

180 B = 270 0^{\circ} + 1296 0^{\circ} n

Divide both sides by

180

\frac{180 B}{180} = 1 5^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Simplify

\frac{180 B}{180} = 1 5^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Simplify

\frac{180 B}{180} : B

\frac{180 B}{180}

Divide the numbers:

\frac{180}{180} = 1

= B

Simplify

1 5^{\circ} + \frac{1296 0 ^{\circ} n}{180} : 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

1 5^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Cancel

1 5^{\circ} : 1 5^{\circ}

1 5^{\circ}

Cancel the common factor:

15

= 1 5^{\circ}

= 1 5^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Cancel

\frac{1296 0 ^{\circ} n}{180} : \frac{36 0 ^{\circ} n}{5}

\frac{1296 0 ^{\circ} n}{180}

Cancel the common factor:

36

= \frac{36 0 ^{\circ} n}{5}

= 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}

Solve

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 27 0^{\circ} + 36 0^{\circ} n : B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 27 0^{\circ} + 36 0^{\circ} n

Multiply by LCM

\frac{18 0 ^{\circ} + 108 B}{36} + \frac{18 0 ^{\circ} + 36 B}{18} = 27 0^{\circ} + 36 0^{\circ} n

Find Least Common Multiplier of

36, 18, 2 : 36

36, 18, 2

Least Common Multiplier (LCM)

Prime factorization of

36 : 2 \cdot 2 \cdot 3 \cdot 3

36

36

divides by

236 = 18 \cdot 2

= 2 \cdot 18

18

divides by

218 = 9 \cdot 2

= 2 \cdot 2 \cdot 9

9

divides by

39 = 3 \cdot 3

= 2 \cdot 2 \cdot 3 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3 \cdot 3

Prime factorization of

18 : 2 \cdot 3 \cdot 3

18

18

divides by

218 = 9 \cdot 2

= 2 \cdot 9

9

divides by

39 = 3 \cdot 3

= 2 \cdot 3 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 3

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Compute a number comprised of factors that appear in at least one of the following:

36, 18, 2

= 2 \cdot 2 \cdot 3 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 \cdot 3 = 36

= 36

Multiply by LCM=

36

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 + \frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 = 27 0^{\circ} \cdot 36 + 36 0^{\circ} n \cdot 36

Simplify

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 + \frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 = 27 0^{\circ} \cdot 36 + 36 0^{\circ} n \cdot 36

Simplify

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36 : 18 0^{\circ} + 108 B

\frac{18 0 ^{\circ} + 108 B}{36} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 18 0 ^{\circ} + 108 B ) \cdot 36}{36}

Cancel the common factor:

36

= 18 0^{\circ} + 108 B

Simplify

\frac{18 0 ^{\circ} + 36 B}{18} \cdot 36 : 2 (36 B + 18 0^{\circ})

\frac{18 0 ^{\circ} + 36 B}{18} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 18 0 ^{\circ} + 36 B ) \cdot 36}{18}

Divide the numbers:

\frac{36}{18} = 2

= 2 (36 B + 18 0^{\circ})

Simplify

27 0^{\circ} \cdot 36 : 972 0^{\circ}

27 0^{\circ} \cdot 36

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 972 0^{\circ}

Multiply the numbers:

3 \cdot 36 = 108

= 972 0^{\circ}

Divide the numbers:

\frac{108}{2} = 54

= 972 0^{\circ}

Simplify

36 0^{\circ} n \cdot 36 : 1296 0^{\circ} n

36 0^{\circ} n \cdot 36

Multiply the numbers:

2 \cdot 36 = 72

= 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 972 0^{\circ} + 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 972 0^{\circ} + 1296 0^{\circ} n

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) = 972 0^{\circ} + 1296 0^{\circ} n

Expand

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ}) : 180 B + 54 0^{\circ}

18 0^{\circ} + 108 B + 2 (36 B + 18 0^{\circ})

Expand

2 (36 B + 18 0^{\circ}) : 72 B + 36 0^{\circ}

2 (36 B + 18 0^{\circ})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = 36 B, c = 18 0^{\circ}

= 2 \cdot 36 B + 36 0^{\circ}

Multiply the numbers:

2 \cdot 36 = 72

= 72 B + 36 0^{\circ}

= 18 0^{\circ} + 108 B + 72 B + 36 0^{\circ}

Simplify

18 0^{\circ} + 108 B + 72 B + 36 0^{\circ} : 180 B + 54 0^{\circ}

18 0^{\circ} + 108 B + 72 B + 36 0^{\circ}

Group like terms

= 108 B + 72 B + 18 0^{\circ} + 36 0^{\circ}

Add similar elements:

108 B + 72 B = 180 B

= 180 B + 18 0^{\circ} + 36 0^{\circ}

Add similar elements:

18 0^{\circ} + 36 0^{\circ} = 54 0^{\circ}

= 180 B + 54 0^{\circ}

= 180 B + 54 0^{\circ}

180 B + 54 0^{\circ} = 972 0^{\circ} + 1296 0^{\circ} n

Move

54 0^{\circ}

to the right side

180 B + 54 0^{\circ} = 972 0^{\circ} + 1296 0^{\circ} n

Subtract

54 0^{\circ}

from both sides

180 B + 54 0^{\circ} - 54 0^{\circ} = 972 0^{\circ} + 1296 0^{\circ} n - 54 0^{\circ}

Simplify

180 B = 918 0^{\circ} + 1296 0^{\circ} n

180 B = 918 0^{\circ} + 1296 0^{\circ} n

Divide both sides by

180

180 B = 918 0^{\circ} + 1296 0^{\circ} n

Divide both sides by

180

\frac{180 B}{180} = 5 1^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Simplify

\frac{180 B}{180} = 5 1^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Simplify

\frac{180 B}{180} : B

\frac{180 B}{180}

Divide the numbers:

\frac{180}{180} = 1

= B

Simplify

5 1^{\circ} + \frac{1296 0 ^{\circ} n}{180} : 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

5 1^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Cancel

5 1^{\circ} : 5 1^{\circ}

5 1^{\circ}

Cancel the common factor:

3

= 5 1^{\circ}

= 5 1^{\circ} + \frac{1296 0 ^{\circ} n}{180}

Cancel

\frac{1296 0 ^{\circ} n}{180} : \frac{36 0 ^{\circ} n}{5}

\frac{1296 0 ^{\circ} n}{180}

Cancel the common factor:

36

= \frac{36 0 ^{\circ} n}{5}

= 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

B = 1 5^{\circ} + \frac{36 0 ^{\circ} n}{5}, B = 5 1^{\circ} + \frac{36 0 ^{\circ} n}{5}

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Frequently Asked Questions (FAQ)

What is the general solution for tan(3B+5)=cot(2B+10) ?
The general solution for tan(3B+5)=cot(2B+10) is B=15+(360n)/5 ,B=51+(360n)/5