sec(420)

Lösung

sec (42 0^{\circ})

2

Schritte zur Lösung

sec (42 0^{\circ})

sec (42 0^{\circ}) = sec (6 0^{\circ})

sec (42 0^{\circ})

Schreibe

42 0^{\circ}

um:

36 0^{\circ} + 6 0^{\circ}

= sec (36 0^{\circ} + 6 0^{\circ})

Verwende die Periodizität von

sec

sec (x + 36 0^{\circ}) = sec (x)

sec (36 0^{\circ} + 6 0^{\circ}) = sec (6 0^{\circ})

= sec (6 0^{\circ})

= sec (6 0^{\circ})

Verwende die folgende triviale Identität:

sec (6 0^{\circ}) = 2

sec (6 0^{\circ})

sec (x)

Periodizitätstabelle mit

36 0^{\circ} n

Zyklus:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 2

= 2

tan (7 4^{\circ})

cos (5 7^{\circ})

sin (9 8^{\circ})

cos (- \frac{5 π}{2})

8 cos (\frac{2 π}{3})