Is cot(B)sec(B)sin(B)=1 ?

The answer to whether cot(B)sec(B)sin(B)=1 is True

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prove cot(B)sec(B)sin(B)=1

prove

cot (B) sec (B) sin (B) = 1

True

Solution steps

cot (B) sec (B) sin (B) = 1

Manipulating left side

cot (B) sec (B) sin (B)

Express with sin, cos

cot (B) sec (B) sin (B)

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= \frac{cos ( B )}{sin ( B )} sec (B) sin (B)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{cos ( B )}{sin ( B )} \cdot \frac{1}{cos ( B )} sin (B)

\frac{cos ( B )}{sin ( B )} \cdot \frac{1}{cos ( B )} sin (B) = 1

\frac{cos ( B )}{sin ( B )} \cdot \frac{1}{cos ( B )} sin (B)

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{cos ( B ) \cdot 1 \cdot sin ( B )}{sin ( B ) cos ( B )}

Cancel the common factor:

cos (B)

= \frac{1 \cdot sin ( B )}{sin ( B )}

Cancel the common factor:

sin (B)

= 1

= 1

= 1

We showed that the two sides could take the same form

\Rightarrow True