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Popular Trigonometria >

tan(θ)>0\land sin(θ)<0

Solução

tan (θ) > 0 and sin (θ) < 0

Solução

Falso para todo θ \in R

Passos da solução

tan (θ) > 0 and sin (θ) < 0

tan (θ) > 0 : πn < θ < \frac{π}{2} + πn

tan (θ) > 0

Se

tan (x) > a

então

arctan (a) + πn < x < \frac{π}{2} + πn

arctan (0) + πn < θ < \frac{π}{2} + πn

Simplificar

arctan (0) : 0

arctan (0)

Utilizar a seguinte identidade trivial:

arctan (0) = 0

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= 0

0 + πn < θ < \frac{π}{2} + πn

Simplificar

πn < θ < \frac{π}{2} + πn

sin (θ) < 0 : - π + 2 πn < θ < 2 πn

sin (θ) < 0

Para

sin (x) < a

, se

- 1 < a \leq 1

então

- π - arcsin (a) + 2 πn < x < arcsin (a) + 2 πn

- π - arcsin (0) + 2 πn < θ < arcsin (0) + 2 πn

Simplificar

- π - arcsin (0) : - π

- π - arcsin (0)

Utilizar a seguinte identidade trivial:

arcsin (0) = 0

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= - π - 0

- π - 0 = - π

= - π

Simplificar

arcsin (0) : 0

arcsin (0)

Utilizar a seguinte identidade trivial:

arcsin (0) = 0

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= 0

- π + 2 πn < θ < 0 + 2 πn

Simplificar

- π + 2 πn < θ < 2 πn

Combinar os intervalos

πn < θ < \frac{π}{2} + πn and - π + 2 πn < θ < 2 πn

Junte intervalos que se sobrepoem

Falso para todo θ \in R

Exemplos populares

sin(θ)<0\land cos(θ)>0

sin (θ) < 0 and cos (θ) > 0

cot(θ)=-1/3 \land cos(θ)>0,sec(θ)

cot (θ) = - \frac{1}{3} and cos (θ) > 0, sec (θ)

tan(θ)=-4/5 \land cos(θ)>0,csc(θ)

tan (θ) = - \frac{4}{5} and cos (θ) > 0, csc (θ)

sin(θ)>0\land cos(θ)<0

sin (θ) > 0 and cos (θ) < 0

sin(θ)<0\land (csc(θ))(cos(θ))>0

sin (θ) < 0 and (csc (θ)) (cos (θ)) > 0