What is the general solution for sin(θ)= 4/5 ,0<= θ<= pi/2 ?

The general solution for sin(θ)= 4/5 ,0<= θ<= pi/2 is θ=0.92729…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

sin(θ)= 4/5 ,0<= θ<= pi/2

sin (θ) = \frac{4}{5}, 0 \leq θ \leq \frac{π}{2}

θ = 0.92729 \dots

Degrees

θ = 53.13010 \dots^{\circ}

Solution steps

sin (θ) = \frac{4}{5}, 0 \leq θ \leq \frac{π}{2}

Apply trig inverse properties

sin (θ) = \frac{4}{5}

General solutions for

sin (θ) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

0 \leq θ \leq \frac{π}{2}

θ = arcsin (\frac{4}{5})

Show solutions in decimal form

θ = 0.92729 \dots

What is the general solution for sin(θ)= 4/5 ,0<= θ<= pi/2 ?
The general solution for sin(θ)= 4/5 ,0<= θ<= pi/2 is θ=0.92729…